Arrange 4, 2, 3, 1 to Form a Divisible by 4 Number

To solve this problem, we will apply the divisibility rule for 4:

A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Therefore, we need to consider pairs from the digits $1, 2, 3,$ and $4$ that can form numbers divisible by 4. Let's list them:

• 12: Not divisible by 4.
• 21: Not divisible by 4.
• 32: Divisible by 4 ($32 \div 4 = 8$).
• 42: Divisible by 4 ($42 \div 4 = 10.5$ - Incorrect!).

From the list above, the only pair that forms a number divisible by 4 is $32$. By setting the last two digits as $32$, we use the remaining digits $1$ and $4$ as the preceding two digits to form the complete number.

Possible numbers using this order include $x132$, where $x$ is any combination of the remaining $1, 4$.

Let's attempt to form a number:
Arrange $3, 1, 2, 4$: $31$ and $24$, yielding 3124.
Verify if it matches our condition as laid in the answer choices.

Looking through our options, only $3124$ fits a number divisible by 4.

Thus, the number 3124 fulfills the condition of divisibility by 4.

Therefore, the solution to the problem is $3124$.