Analyzing Parabola Properties: Vertex on X-axis with Upward Orientation

To evaluate the statement about the parabola, we need to understand its properties precisely:

Step 1: Given the parabola's vertex is on the x-axis, we can write its equation in the form $y = a(x-h)^2$, where $a > 0$ indicates that it opens upwards.

Step 2: The vertex form of a quadratic function has the vertex $(h, 0)$ with the vertex lying directly on the x-axis. Since $a > 0$, the parabola opens upwards, implying $(h, 0)$ is the minimum point.

Step 3: For points other than the vertex, $(x-h)^2$ is always non-negative. Since $a$ is positive, $y = a(x-h)^2 \geq 0$. Therefore, the function value at the vertex is zero, and for all other $x$, the function value is positive.

Step 4: Analyze if the function can be negative: With $a > 0$, the value $a(x-h)^2$ cannot be negative for any value of $x$.

Conclusion: The given statement that the function is "always negative except for the vertex point" is incorrect since outside the vertex, the function is always non-negative and can be positive. Hence, the statement is incorrect.

Therefore, the correct answer is Incorrect.