Arithmetic Sequence: Is 32.5 the nth Term When First Term is 7 and Difference is 8.5?

Arithmetic Sequences with Term Position Verification

Given the series whose first element is 7.

Each term of the series is greater by 8.5 of its predecessor.

Is the number 32.5 an element in the series?

If so, please indicate your place in the series.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Is the number 32.5 in the sequence?
00:06 Let's use the sequence formula
00:17 Let's substitute appropriate values according to the given data and solve
00:23 If the value of N turns out to be a positive whole number, then the number is a term in the sequence
00:45 Let's properly expand the brackets and multiply by each factor
01:04 We want to isolate N
01:27 This is the value of N and the position of the term in the sequence
01:34 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Given the series whose first element is 7.

Each term of the series is greater by 8.5 of its predecessor.

Is the number 32.5 an element in the series?

If so, please indicate your place in the series.

2

Step-by-step solution

To determine if 32.5 is an element in the series, we will follow these steps:

  • Step 1: Identify the formula for the n n -th term of an arithmetic sequence.
  • Step 2: Substitute the given values and solve for n n .
  • Step 3: Check if n n is a positive integer.

Step 1: We know the n n -th term formula for an arithmetic sequence is given by:

an=a1+(n1)d a_n = a_1 + (n-1) \cdot d

where a1=7 a_1 = 7 and d=8.5 d = 8.5 .

Step 2: To find if 32.5 is in the sequence, substitute it as an a_n :

32.5=7+(n1)8.5 32.5 = 7 + (n-1) \cdot 8.5

Simplify and solve for n n :

32.5=7+8.5n8.5 32.5 = 7 + 8.5n - 8.5

32.5=1.5+8.5n 32.5 = -1.5 + 8.5n

Add 1.5 to both sides:

34=8.5n 34 = 8.5n

Divide by 8.5 to solve for n n :

n=348.5 n = \frac{34}{8.5}

n=4 n = 4

Step 3: Verify that n n is a positive integer.

Since n=4 n = 4 is a positive integer, 32.5 is indeed in the series, and it is the 4th term.

Therefore, the solution to the problem is Yes, 4 4 .

3

Final Answer

Yes, 4 4

Key Points to Remember

Essential concepts to master this topic
  • Formula: Use an=a1+(n1)d a_n = a_1 + (n-1) \cdot d for nth term calculation
  • Technique: Set 32.5 = 7 + (n-1) × 8.5 and solve for n
  • Check: Verify n is a positive integer: n = 4 means 4th term ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to subtract 1 from n in the formula
    Don't use an=a1+nd a_n = a_1 + n \cdot d = wrong position! This formula assumes we start counting from n=0 instead of n=1, shifting every term position. Always use an=a1+(n1)d a_n = a_1 + (n-1) \cdot d with the (n-1) term.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

What does it mean for a number to be 'in the series'?

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A number is 'in the series' if it appears as one of the terms when you list out the sequence. For example, our sequence is 7, 15.5, 24, 32.5, 41... so 32.5 is the 4th term!

Why do we need n to be a positive integer?

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The position number n must be a positive integer because we can't have a 'fractional position' like the 2.5th term. If n comes out as a fraction or negative number, the given number isn't in the sequence.

How do I verify my answer is correct?

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Substitute n = 4 back into the formula: a4=7+(41)×8.5=7+25.5=32.5 a_4 = 7 + (4-1) \times 8.5 = 7 + 25.5 = 32.5 ✓. The calculation should give you the original number!

What if I get a decimal when solving for n?

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If n comes out as a decimal or fraction, then the number is not in the sequence. Only whole number positions (1st, 2nd, 3rd, etc.) exist in arithmetic sequences.

Can the common difference be negative?

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Yes! A negative common difference creates a decreasing sequence. The same formula works - just be careful with your arithmetic when the difference is negative.

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