Gabriela runs 4km at a speed of 8km/h, then another 6 km.
Her average speed is km/h.
Express her speed during the last 6 km in terms of X.
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Gabriela runs 4km at a speed of 8km/h, then another 6 km.
Her average speed is km/h.
Express her speed during the last 6 km in terms of X.
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Time for the first segment is hours.
Time for the second segment is hours.
Step 2: Calculate the total time:
Total time hours.
The total distance is = 10 km.
The average speed given is km/h, so:
.
Solving for :
Cross-multiply to clear the fraction:
Simplify:
Multiply numerator and denominator by 2 to simplify:
Further simplification:
Therefore, the solution to the problem is the speed during the last 6 km is km/h.
km/h
What is the average speed according to the data?
Because Gabriela spends different amounts of time at each speed! She runs 4 km at 8 km/h (0.5 hours) but 6 km at the unknown speed. The time spent matters for calculating average speed.
Remember that time = distance ÷ speed. So the first segment takes hours, and the second takes hours where v is the unknown speed.
The average speed is given as 5x km/h, where x is just a variable. This means the average speed depends on the value of x, and we need to express the unknown speed in terms of x too.
Complex fractions like are normal in algebra! This shows the relationship between the unknown speed and the variable x. Don't try to simplify it further unless you know x's value.
Pick a test value for x (like x = 1), calculate the resulting speed, then verify the average speed equals 5x using the total distance ÷ total time formula.
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