Calculate Gabriela's Speed: Determining X for Her Last 6 km

Gabriela runs 4km at a speed of 8km/h, then another 6 km.

Her average speed is 5x 5x km/h.

Express her speed during the last 6 km in terms of X.

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1

Understand the problem

Gabriela runs 4km at a speed of 8km/h, then another 6 km.

Her average speed is 5x 5x km/h.

Express her speed during the last 6 km in terms of X.

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the time taken for each segment.
  • Step 2: Use the average speed formula to connect these times and speed.
  • Step 3: Solve the resulting equation for the unknown speed vv.

Now, let's work through each step:

Step 1: Time for the first segment is 48=0.5\frac{4}{8} = 0.5 hours.

Time for the second segment is 6v\frac{6}{v} hours.

Step 2: Calculate the total time:

Total time T=0.5+6vT = 0.5 + \frac{6}{v} hours.

The total distance is 4+64 + 6 = 10 km.

The average speed given is 5x5x km/h, so:

5x=10T=100.5+6v5x = \frac{10}{T} = \frac{10}{0.5 + \frac{6}{v}}.

Solving for vv:

Cross-multiply to clear the fraction:

5x(0.5+6v)=105x \left(0.5 + \frac{6}{v}\right) = 10

Simplify:

2.5x+30xv=102.5x + \frac{30x}{v} = 10

30xv=102.5x\frac{30x}{v} = 10 - 2.5x

v=30x102.5xv = \frac{30x}{10 - 2.5x}

Multiply numerator and denominator by 2 to simplify:

v=60x205xv = \frac{60x}{20 - 5x}

Further simplification:

v=12x4xv = \frac{12x}{4 - x}

Therefore, the solution to the problem is the speed during the last 6 km is 12x4x \frac{12x}{4-x} km/h.

3

Final Answer

12x4x \frac{12x}{4-x} km/h

Practice Quiz

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What is the average speed according to the data?

TravelTimekm/hDistance3122.570400100210400250

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