Ricardo travels 18 km at a speed of X km/h and then doubles his speed.
Then he covers another 12 km, rests for half an hour, and then continues at his initial speed for another 10 km.
What is his average speed?
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Ricardo travels 18 km at a speed of X km/h and then doubles his speed.
Then he covers another 12 km, rests for half an hour, and then continues at his initial speed for another 10 km.
What is his average speed?
To solve this problem, we'll follow these steps:
Step 1: Calculate the total distance traveled.
Step 2: Determine the time taken for each segment of the journey.
Step 3: Use these times to calculate the total journey time.
Step 4: Apply the average speed formula using the total distance and total time.
Let's work through each step:
Step 1: Calculate the total distance traveled. Ricardo travels:
18 km in the first segment,
12 km in the second segment,
10 km in the third segment.
Total distance is km.
Step 2: Determine the time taken for each segment of the journey.
First segment: hours.
Second segment: hours (since he doubles his speed to ).
Rest: hour.
Third segment: hours.
Step 3: Calculate the total journey time by adding all the parts together:
Total time = .
Convert into a fraction with common denominator :
.
So, total time becomes hours.
Step 4: Apply the average speed formula:
km/h.
Thus, the average speed of Ricardo's journey is km/h.
km/h
What is the average speed according to the data?
Average speed measures the overall rate of covering distance during the entire journey, including stops. If Ricardo takes 30 minutes to rest, that's part of his total trip time!
Find a common denominator! For , multiply the first fraction by and the second by to get .
If his initial speed is X km/h, then doubling means his new speed becomes 2X km/h. This means he covers the same distance in half the time during that segment.
Check your total time calculation carefully! The correct total time is hours, giving average speed of km/h.
You could use decimal values for X, but keeping it as a variable with fractions shows the general solution. The fractional form works for any speed X!
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