Calculate the Average Speed: Turtle's Multi-Speed Journey to the Sea

Question

A turtle starts its journey towards the sea 38 meters away from it.

In the first 20 meters, its speed is X km/h. It rests for 20 minutes and then continues its journey at a speed 114 1\frac{1}{4} times greater than its previous speed.

What is the average speed?

Video Solution

Step-by-Step Solution

To calculate the average speed of the turtle, we'll proceed with the following steps:

  • Step 1: Convert 38 meters to kilometers, which gives us 0.038 0.038 km.
    The first segment of 20 meters is 0.020 0.020 km, and the second segment of 18 meters is 0.018 0.018 km.
  • Step 2: Calculate the time taken for the first segment.
    The speed is X X km/h for the first segment. The time is given by:
  • t1=0.020X hours t_1 = \frac{0.020}{X} \text{ hours}
  • Step 3: Calculate the time taken for the second segment.
    The speed for the second segment is 1.25X 1.25X km/h. The time is:
  • t2=0.0181.25X hours t_2 = \frac{0.018}{1.25X} \text{ hours}
  • Step 4: Convert the rest time of 20 minutes into hours, which yields 2060=13\frac{20}{60} = \frac{1}{3} hours.
  • Step 5: Calculate the total time taken by adding the time for the two travel segments and the rest time:
  • ttotal=t1+13+t2 t_{\text{total}} = t_1 + \frac{1}{3} + t_2 ttotal=0.020X+13+0.0181.25X t_{\text{total}} = \frac{0.020}{X} + \frac{1}{3} + \frac{0.018}{1.25X}
  • Step 6: Calculate the average speed using the formula for average speed, which is the total distance divided by the total time:
  • Average Speed=0.038ttotal \text{Average Speed} = \frac{0.038}{t_{\text{total}}}
  • Step 7: Simplify the expression:
    Calculate the times:
  • - 0.020X\frac{0.020}{X} hours - 0.0181.25X=0.0185X4=0.018×45X=0.0725X\frac{0.018}{1.25X} = \frac{0.018}{\frac{5X}{4}} = \frac{0.018 \times 4}{5X} = \frac{0.072}{5X} - Total time = 0.020X+13(5X)+0.0725X\frac{0.020X + \frac{1}{3}(5X) + 0.072}{5X}
  • Step 8: Simplify the equation:
  • Total Time=0.02×5+1.666667×5X+0.0725X \text{Total Time} = \frac{0.02 \times 5 + 1.666667 \times 5X + 0.072}{5X} =0.1+1.666667X+0.0725X = \frac{0.1 + 1.666667X + 0.072}{5X} =0.172+1.666667X5X = \frac{0.172 + 1.666667X}{5X}
  • Calculate the average speed:
  • Average Speed=0.0380.172+1.666667X5X=0.038×5X0.172+1.666667X \text{Average Speed} = \frac{0.038}{\frac{0.172 + 1.666667X}{5X}} = \frac{0.038 \times 5X}{0.172 + 1.666667X} =0.19X0.172+1.666667X = \frac{0.19X}{0.172 + 1.666667X}

    Thus, after calculation and simplification, the correct choice for the average speed is:

    142.5x129+1250x \frac{142.5x}{129+1250x} km/h

Answer

142.5x129+1250x \frac{142.5x}{129+1250x} km/h