Calculate Length BB₁: 3D Box Geometry with Given Distance 18

Calculate the length of BB1 BB_1 in the box shown in the diagram.

aaa181818AAABBBCCCDDDAAA111BBB111CCC111DDD111

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find BB1
00:03 Each face in the box is a rectangle, therefore opposite sides are equal
00:09 Let's substitute the side value according to the given data
00:16 Each face in the box is a rectangle, therefore all angles are right angles
00:23 Now we'll use the Pythagorean theorem in triangle A1D1D to find DD1
00:37 Let's substitute appropriate values and solve for DD1
00:44 Isolate DD1
00:52 This is the height DD1
00:59 Each face in the box is a rectangle, therefore opposite sides are equal
01:05 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Calculate the length of BB1 BB_1 in the box shown in the diagram.

aaa181818AAABBBCCCDDDAAA111BBB111CCC111DDD111

3

Final Answer

324−a2 \sqrt{324-a^2}

Practice Quiz

Test your knowledge with interactive questions

Consider a right-angled triangle, AB = 8 cm and AC = 6 cm.
Calculate the length of side BC.

666888BBBCCCAAA

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Pythagorean Theorem questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations

Using the Pythagorean Theorem in Cuboids

Calculate the Diagonal of a Rectangular Prism: Dimensions a/2, 3b, and a+b
Click to solve
Orthohedron Problem: Finding BE When CG = 1/2 HG
Click to solve