Calculate the Diagonal of a Rectangular Prism: Dimensions a/2, 3b, and a+b

3D Diagonal Formula with Algebraic Expressions

Look at the rectangular prism below.


Its height is a2 \frac{a}{2} , its length is 3b 3b , and its width is a+b a+b .

Calculate the diagonal of the rectangular prism.

a+ba+ba+b3b3b3b

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Calculate the diagonal of the box
00:03 Draw the face diagonal, and mark it with X
00:08 Use the Pythagorean theorem to find the diagonal expression
00:25 Collect terms and arrange
00:30 This is the face diagonal expression
00:38 Draw the triangle where the hypotenuse is the box diagonal, mark it with Y
00:46 Use the Pythagorean theorem to find the box diagonal expression
00:51 Substitute the X value we found
01:04 Collect terms and arrange
01:08 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Look at the rectangular prism below.


Its height is a2 \frac{a}{2} , its length is 3b 3b , and its width is a+b a+b .

Calculate the diagonal of the rectangular prism.

a+ba+ba+b3b3b3b

2

Step-by-step solution

To calculate the diagonal of the rectangular prism, we use the formula for the diagonal dd in a cuboid: d=l2+w2+h2 d = \sqrt{l^2 + w^2 + h^2} where l=3bl = 3b, w=a+bw = a+b, and h=a2h = \frac{a}{2}.

First, we compute each squared term:

  • Length squared: (3b)2=9b2(3b)^2 = 9b^2
  • Width squared: (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2
  • Height squared: (a2)2=a24\left(\frac{a}{2}\right)^2 = \frac{a^2}{4}

Now, adding these values: l2+w2+h2=9b2+(a2+2ab+b2)+a24 l^2 + w^2 + h^2 = 9b^2 + (a^2 + 2ab + b^2) + \frac{a^2}{4} Combine the terms: =9b2+a2+2ab+b2+a24 = 9b^2 + a^2 + 2ab + b^2 + \frac{a^2}{4} Simplify: =a24+a2+10b2+2ab = \frac{a^2}{4} + a^2 + 10b^2 + 2ab Notice that a2+a24=4a24+a24=5a24a^2 + \frac{a^2}{4} = \frac{4a^2}{4} + \frac{a^2}{4} = \frac{5a^2}{4}.

Thus, the diagonal is: d=5a24+2ab+10b2 d = \sqrt{\frac{5a^2}{4} + 2ab + 10b^2} This expression matches choice 1 in the given multiple-choice answers.

Therefore, the solution to the problem is 54a2+2ab+10b2\sqrt{\frac{5}{4}a^2 + 2ab + 10b^2}.

3

Final Answer

54a2+2ab+10b2 \sqrt{\frac{5}{4}a^2+2ab+10b^2}

Key Points to Remember

Essential concepts to master this topic
  • Formula: 3D diagonal uses d=l2+w2+h2 d = \sqrt{l^2 + w^2 + h^2}
  • Technique: Expand (a+b)2=a2+2ab+b2 (a+b)^2 = a^2 + 2ab + b^2 carefully
  • Check: Combine like terms: a2+a24=5a24 a^2 + \frac{a^2}{4} = \frac{5a^2}{4}

Common Mistakes

Avoid these frequent errors
  • Adding dimensions instead of their squares
    Don't add a/2 + 3b + (a+b) = diagonal! This gives a linear expression, not the diagonal length. The diagonal formula requires squaring each dimension first, then adding, then taking the square root. Always use d=l2+w2+h2 d = \sqrt{l^2 + w^2 + h^2} .

Practice Quiz

Test your knowledge with interactive questions

Consider a right-angled triangle, AB = 8 cm and AC = 6 cm.
Calculate the length of side BC.

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FAQ

Everything you need to know about this question

Why do we square each dimension first?

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The 3D diagonal formula comes from applying the Pythagorean theorem twice - once for the base diagonal, then again for the space diagonal. Each application requires squaring the sides!

How do I expand (a+b)² correctly?

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Use the pattern (a+b)2=a2+2ab+b2 (a+b)^2 = a^2 + 2ab + b^2 . Don't forget the middle term 2ab - it's the most commonly missed part!

What do I do with the fraction a/2?

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Square it like any other term: (a2)2=a24 \left(\frac{a}{2}\right)^2 = \frac{a^2}{4} . Remember that squaring a fraction means squaring both numerator and denominator.

How do I combine a² and a²/4?

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Convert to the same denominator: a2=4a24 a^2 = \frac{4a^2}{4} , so a2+a24=4a2+a24=5a24 a^2 + \frac{a^2}{4} = \frac{4a^2 + a^2}{4} = \frac{5a^2}{4}

Can I simplify the final answer further?

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The answer 5a24+2ab+10b2 \sqrt{\frac{5a^2}{4} + 2ab + 10b^2} is already in simplest form. You cannot factor out terms from under a square root unless they form perfect squares.

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