What is the area of the rectangle whose length meters and the width ?
We have hundreds of course questions with personalized recommendations + Account 100% premium
What is the area of the rectangle whose length meters and the width ?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: Convert the mixed numbers to improper fractions.
Step 2: Multiply the improper fractions.
Step 3: Simplify the resulting fraction, if possible.
Step 4: Convert back to a mixed number, since is an improper fraction:
Divide 133 by 18 to get the mixed number:
remainder .
Thus, .
Therefore, the area of the rectangle is square meters.
\( \frac{2}{3}\times\frac{5}{7}= \)
Because mixed numbers represent a single value, not separate parts! When you multiply , you need to account for all combinations of multiplication, which only happens when you convert to improper fractions first.
Use the formula: Improper fraction = (whole × denominator + numerator) ÷ denominator. For : (3 × 6 + 1) ÷ 6 =
Check if you can simplify first! For , since 133 and 18 share no common factors, it's already in simplest form. Then convert: 133 ÷ 18 = 7 remainder 7, so .
Estimate first! is about 3, and is about 2.3, so the area should be around 3 × 2.3 = 6.9. Our answer ≈ 7.4 is close!
Take it step by step:
Don't rush - each step builds on the previous one!
Get unlimited access to all 18 Operations with Fractions questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime