What is the area of the rectangle whose length meters and the width ?
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What is the area of the rectangle whose length meters and the width ?
To solve this problem, we'll proceed as follows:
Let's work through these steps:
Step 1: First, convert the mixed numbers to improper fractions.
The length is meters. Convert this to an improper fraction:
The width is meters. Convert this to an improper fraction:
Step 2: Multiply these improper fractions to find the area.
Thus, the area of the rectangle in square meters is:
Simplify the fraction :
Both the numerator and the denominator can be divided by 6:
Step 3: Convert the improper fraction back to a mixed number:
Therefore, the area of the rectangle is square meters.
\( \frac{2}{3}\times\frac{5}{7}= \)
Converting makes multiplication much easier! When you have , you can multiply straight across: numerator × numerator and denominator × denominator.
Use this formula: multiply the whole number by the denominator, then add the numerator. So .
It's much harder and more error-prone! You'd need to use the distributive property multiple times. Converting to improper fractions first makes the problem much simpler and reduces mistakes.
Find the greatest common factor (GCF) of 126 and 12, which is 6. Then divide both: .
Because we're finding area! When you multiply two lengths (meters × meters), you get square meters. Think of it as counting unit squares that fit inside the rectangle.
Divide the numerator by the denominator: 21 ÷ 2 = 10 remainder 1. So .
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