ΔBCE≅ΔFED
Calculate the perimeter of the rectangle EDGF.
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ΔBCE≅ΔFED
Calculate the perimeter of the rectangle EDGF.
To find the perimeter of rectangle EDGF, we will follow these steps:
Now, let's proceed with the solution:
Step 1: Given and are congruent triangles, their corresponding sides are equal. Thus, since , it follows that .
Step 2: From the configuration of the rectangle, note that (same as AE) is given to be 8, hence because EDGF is a rectangle.
Step 3: The perimeter of rectangle EDGF can be calculated using:
Therefore, the solution to the problem is that the perimeter of rectangle EDGF is 28.
28
Look at the rectangle below.
Side DC has a length of 1.5 cm and side AD has a length of 9.5 cm.
What is the perimeter of the rectangle?
Look at the order of vertices in the congruence statement! In , the first letters (B and F) correspond, second letters (C and E) correspond, and third letters (E and D) correspond.
From , vertex C corresponds to vertex E, and vertex E corresponds to vertex D. So side BC corresponds to side FE, and side CE corresponds to side ED. Since BC = 6, we get FE = 6, not ED = 6.
Look at the diagram! The side EF is marked as 8, and since EDGF is a rectangle, opposite sides are equal. So EF = DG = 8, making the rectangle dimensions 6 × 8.
Perimeter = 2 × (length + width). Since rectangles have two pairs of equal sides, you add length + width once, then multiply by 2 to account for both pairs.
Absolutely! For rectangle EDGF: ED + DG + GF + FE = 6 + 8 + 6 + 8 = 28. Both methods give the same answer, so use whichever feels easier to you!
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