Given an cuboid with side length 7 cm, the second side is 10% smaller than the first, and the third is 10% larger than the second, what is its surface area?
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Given an cuboid with side length 7 cm, the second side is 10% smaller than the first, and the third is 10% larger than the second, what is its surface area?
To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We are given that the first side length is cm. The second side is smaller than the first side. Calculate the second side length:
The third side is larger than the second side. Calculate the third side length:
Step 2: Now calculate the surface area using the formula :
Let , , and . Substitute into the formula:
Calculate each part:
Add these results together:
Thus, the surface area is:
Therefore, the solution to the problem is .
272.538 cm².
Identify the correct 2D pattern of the given cuboid:
You need all three dimensions to use the surface area formula! Each percentage change builds on the previous dimension: first side → second side → third side. Calculate them step by step.
10% smaller means multiply by 0.9 (or subtract 10% from 100%). So 7 cm × 0.9 = 6.3 cm. Don't just subtract 1 cm!
Think of it as 2 times the sum of all face areas: . Each pair appears twice because opposite faces are identical!
Yes! 10% larger means multiply by 1.1 (add 10% to 100%). So 6.3 cm × 1.1 = 6.93 cm. The method works for any percentage change.
Keep all decimal places during calculations, then round your final answer appropriately. Rounding too early can lead to accumulating errors in your surface area result.
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