Given an cuboid with side length 7 cm, the second side is 10% smaller than the first, and the third is 10% larger than the second, what is its surface area?
To solve this problem, we'll follow these steps:
- Step 1: Identify the dimensions of the cuboid using the modifications given.
- Step 2: Apply the surface area formula for the cuboid using these dimensions.
Now, let's work through each step:
Step 1: We are given that the first side length is 7 cm. The second side is 10% smaller than the first side. Calculate the second side length:
Second Side=7cm−0.1×7cm=7cm−0.7cm=6.3cm
The third side is 10% larger than the second side. Calculate the third side length:
Third Side=6.3cm+0.1×6.3cm=6.3cm+0.63cm=6.93cm
Step 2: Now calculate the surface area using the formula 2(lw+lh+wh):
Let l=7cm, w=6.3cm, and h=6.93cm. Substitute into the formula:
Surface Area=2(7×6.3+7×6.93+6.3×6.93)
Calculate each part:
7×6.3=44.1
7×6.93=48.51
6.3×6.93=43.659
Add these results together:
44.1+48.51+43.659=136.269
Thus, the surface area is:
2×136.269=272.538cm2
Therefore, the solution to the problem is 272.538 cm2.