Examples with solutions for Surface Area of a Cuboid: Calculation using percentages

Exercise #1

Look at the orthohedron shown in the figure below.

Side b is 20% longer than side a.

Side c is 20% longer than side b.

Calculate a, c, and b given that the surface area of the orthohedron is 436 cm².

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Video Solution

Step-by-Step Solution

First, we'll express b b and c c in terms of a a :
b=1.2aandc=1.44a b = 1.2a \quad \text{and} \quad c = 1.44a

Next, substitute these into the surface area formula for a cuboid:

2(ab+bc+ca)=436 2(ab + bc + ca) = 436

ab=a(1.2a)=1.2a2 ab = a \cdot (1.2a) = 1.2a^2

bc=(1.2a)(1.44a)=1.728a2 bc = (1.2a) \cdot (1.44a) = 1.728a^2

ca=(1.44a)a=1.44a2 ca = (1.44a) \cdot a = 1.44a^2

Substitute these into the formula:

2(1.2a2+1.728a2+1.44a2)=436 2(1.2a^2 + 1.728a^2 + 1.44a^2) = 436

Simplify inside the parentheses:

24.368a2=436 2 \cdot 4.368a^2 = 436

8.736a2=436 8.736a^2 = 436

Solve for a2 a^2 :

a2=4368.736 a^2 = \frac{436}{8.736}

a249.93 a^2 \approx 49.93

Taking the square root, we find:

a49.937.06 a \approx \sqrt{49.93} \approx 7.06

Now, find b b and c c :

b=1.2a=1.2×7.068.47 b = 1.2a = 1.2 \times 7.06 \approx 8.47

c=1.44a=1.44×7.0610.17 c = 1.44a = 1.44 \times 7.06 \approx 10.17

Therefore, the dimensions of the orthohedron are:

a=7.06 a = 7.06 , b=8.47 b = 8.47 , and c=10.17 c = 10.17 .

Answer

a=7.06, b=8.47, c=10.17

Exercise #2

Given an cuboid with side length 7 cm, the second side is 10% smaller than the first, and the third is 10% larger than the second, what is its surface area?

Video Solution

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the dimensions of the cuboid using the modifications given.
  • Step 2: Apply the surface area formula for the cuboid using these dimensions.

Now, let's work through each step:
Step 1: We are given that the first side length is 77 cm. The second side is 10%10\% smaller than the first side. Calculate the second side length:
Second Side=7cm0.1×7cm=7cm0.7cm=6.3cm \text{Second Side} = 7\,\text{cm} - 0.1 \times 7\,\text{cm} = 7\,\text{cm} - 0.7\,\text{cm} = 6.3\,\text{cm}

The third side is 10%10\% larger than the second side. Calculate the third side length:
Third Side=6.3cm+0.1×6.3cm=6.3cm+0.63cm=6.93cm \text{Third Side} = 6.3\,\text{cm} + 0.1 \times 6.3\,\text{cm} = 6.3\,\text{cm} + 0.63\,\text{cm} = 6.93\,\text{cm}

Step 2: Now calculate the surface area using the formula 2(lw+lh+wh)2(lw + lh + wh):
Let l=7cml = 7\,\text{cm}, w=6.3cmw = 6.3\,\text{cm}, and h=6.93cmh = 6.93\,\text{cm}. Substitute into the formula:
Surface Area=2(7×6.3+7×6.93+6.3×6.93) \text{Surface Area} = 2 \left( 7 \times 6.3 + 7 \times 6.93 + 6.3 \times 6.93 \right)

Calculate each part:
7×6.3=44.17 \times 6.3 = 44.1
7×6.93=48.517 \times 6.93 = 48.51
6.3×6.93=43.6596.3 \times 6.93 = 43.659

Add these results together:
44.1+48.51+43.659=136.269 44.1 + 48.51 + 43.659 = 136.269

Thus, the surface area is:
2×136.269=272.538cm2 2 \times 136.269 = 272.538 \,\text{cm}^2

Therefore, the solution to the problem is 272.538 cm2\textbf{272.538 cm}^2.

Answer

272.538 cm².

Exercise #3

What is the surface area of the quadrangular cuboid in the diagram? aaaxxx

Given a constitutes 80% of x

Video Solution

Answer

4.48x2 4.48x^2

Exercise #4

Given the unfolding of the quadrangular cuboid where the area of the square face is 70% smaller than the area of the rectangular face.

Find the surface of the cuboid.

40cm²

Video Solution

Answer

613.33 cm².

Exercise #5

What is the surface area of the given shape given the lengths of the sides of the small cuboid are 40% of the lengths of the corresponding sides in the large cuboid?

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Video Solution

Answer

569.2 cm².