Calculate the Final Leg: Distance in 1/4 Hour at 66 2/3 km/h

Question

Rodney rides a motorcycle for 13 \frac{1}{3} of an hour over a distance of 30 km, stops to rest for 16 \frac{1}{6} of an hour, then continues for 14 \frac{1}{4} of an hour.

His average speed is 6623 66\frac{2}{3} km/h.

How far does he ride in the last quarter of an hour of his trip?

Video Solution

Step-by-Step Solution

To solve this problem, we need to follow these steps:

  • Step 1: Calculate the total time of the trip.
  • Step 2: Use the average speed formula to find the total distance traveled.
  • Step 3: Determine the distance traveled during the last 14\frac{1}{4} hour by using known values.

Let's work through each step in detail:

Step 1: Calculate the total time of the trip.
The total time of the trip is the sum of all segments: riding, resting, and continuing.
Total time = 13\frac{1}{3} hour riding + 16\frac{1}{6} hour rest + 14\frac{1}{4} hour riding = 26+16+1.56=4.56=34\frac{2}{6} + \frac{1}{6} + \frac{1.5}{6} = \frac{4.5}{6} = \frac{3}{4} hour.

Step 2: Find the total distance using the given average speed.
Average speed formula: Average speed=Total distanceTotal time \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} .
Given that average speed is 6623km/h66 \frac{2}{3} \, \text{km/h} or 2003km/h\frac{200}{3} \, \text{km/h},
Total distance = Average speed ×\times Total time
= 2003×34=50km\frac{200}{3} \times \frac{3}{4} = 50 \, \text{km}.

Step 3: Determine the distance covered in the last 14\frac{1}{4} hour segment.
Subtract the known initial 30 km from the total distance of 50 km:
Distance covered in the last 14\frac{1}{4} hour = Total distance - Distance in first segment
= 50km30km=20km50 \, \text{km} - 30 \, \text{km} = 20 \, \text{km}.

Therefore, the distance Rodney rides in the last quarter of an hour of his trip is 20 km \textbf{20 km} .

Answer

20 20 km