Calculate the Final Leg: Distance in 1/4 Hour at 66 2/3 km/h

Average Speed Problems with Mixed Numbers

Rodney rides a motorcycle for 13 \frac{1}{3} of an hour over a distance of 30 km, stops to rest for 16 \frac{1}{6} of an hour, then continues for 14 \frac{1}{4} of an hour.

His average speed is 6623 66\frac{2}{3} km/h.

How far does he ride in the last quarter of an hour of his trip?

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1

Understand the problem

Rodney rides a motorcycle for 13 \frac{1}{3} of an hour over a distance of 30 km, stops to rest for 16 \frac{1}{6} of an hour, then continues for 14 \frac{1}{4} of an hour.

His average speed is 6623 66\frac{2}{3} km/h.

How far does he ride in the last quarter of an hour of his trip?

2

Step-by-step solution

To solve this problem, we need to follow these steps:

  • Step 1: Calculate the total time of the trip.
  • Step 2: Use the average speed formula to find the total distance traveled.
  • Step 3: Determine the distance traveled during the last 14\frac{1}{4} hour by using known values.

Let's work through each step in detail:

Step 1: Calculate the total time of the trip.
The total time of the trip is the sum of all segments: riding, resting, and continuing.
Total time = 13\frac{1}{3} hour riding + 16\frac{1}{6} hour rest + 14\frac{1}{4} hour riding = 26+16+1.56=4.56=34\frac{2}{6} + \frac{1}{6} + \frac{1.5}{6} = \frac{4.5}{6} = \frac{3}{4} hour.

Step 2: Find the total distance using the given average speed.
Average speed formula: Average speed=Total distanceTotal time \text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} .
Given that average speed is 6623km/h66 \frac{2}{3} \, \text{km/h} or 2003km/h\frac{200}{3} \, \text{km/h},
Total distance = Average speed ×\times Total time
= 2003×34=50km\frac{200}{3} \times \frac{3}{4} = 50 \, \text{km}.

Step 3: Determine the distance covered in the last 14\frac{1}{4} hour segment.
Subtract the known initial 30 km from the total distance of 50 km:
Distance covered in the last 14\frac{1}{4} hour = Total distance - Distance in first segment
= 50km30km=20km50 \, \text{km} - 30 \, \text{km} = 20 \, \text{km}.

Therefore, the distance Rodney rides in the last quarter of an hour of his trip is 20 km \textbf{20 km} .

3

Final Answer

20 20 km

Key Points to Remember

Essential concepts to master this topic
  • Formula: Average speed equals total distance divided by total time
  • Technique: Convert mixed numbers like 6623 66\frac{2}{3} to 2003 \frac{200}{3}
  • Check: Total distance minus known segments equals remaining distance ✓

Common Mistakes

Avoid these frequent errors
  • Using riding time instead of total time for average speed
    Don't use just riding time (13+14=712 \frac{1}{3} + \frac{1}{4} = \frac{7}{12} hour) in average speed formula = wrong total distance! Rest time counts in the total trip time. Always include ALL time segments: riding + rest + riding = 34 \frac{3}{4} hour total.

Practice Quiz

Test your knowledge with interactive questions

What is the average speed according to the data?

TravelTimekm/hDistance3122.570400100210400250

FAQ

Everything you need to know about this question

Why does rest time count toward average speed if he's not moving?

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Average speed measures the overall rate for the entire trip duration. Even though Rodney stops for 16 \frac{1}{6} hour, this rest period is part of his total travel time from start to finish.

How do I add fractions with different denominators like 1/3 + 1/6 + 1/4?

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Find the LCD (Least Common Denominator) of 3, 6, and 4, which is 12. Convert each fraction: 13=412 \frac{1}{3} = \frac{4}{12} , 16=212 \frac{1}{6} = \frac{2}{12} , 14=312 \frac{1}{4} = \frac{3}{12} , then add to get 912=34 \frac{9}{12} = \frac{3}{4} .

What's the easiest way to convert 66 2/3 to an improper fraction?

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Multiply the whole number by the denominator and add the numerator: 66×3+2=198+2=200 66 \times 3 + 2 = 198 + 2 = 200 . So 6623=2003 66\frac{2}{3} = \frac{200}{3} .

Why can't I just use distance = speed × time for the last segment?

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We don't know Rodney's speed during the last 14 \frac{1}{4} hour - only his average speed for the whole trip. The average speed formula gives us total distance, then we subtract known distances to find the remaining segment.

How do I check if 20 km in 1/4 hour makes sense?

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Calculate the speed: 20 km14 hour=20×4=80 km/h \frac{20 \text{ km}}{\frac{1}{4} \text{ hour}} = 20 \times 4 = 80 \text{ km/h} . This is faster than his average speed of 6623 66\frac{2}{3} km/h, which makes sense since he was slower in the first segment (30 km in 13 \frac{1}{3} hour = 90 km/h).

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