Calculate the First Four Terms of n³ Sequence: Cube Number Series

Cube Number Sequences with Integer Terms

For the series n3 n^3

Find the first four terms.

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the first four terms
00:06 Let's substitute the desired term position in the sequence formula and solve
00:23 This is the first term in the sequence
00:29 We'll use the same method to find the next terms
00:36 Let's substitute the desired term position in the sequence formula and solve
00:45 This is the second term
00:49 Let's substitute the desired term position in the sequence formula and solve
01:00 This is the third term
01:22 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

For the series n3 n^3

Find the first four terms.

2

Step-by-step solution

To solve for the first four terms of the series n3 n^3 , we follow these steps:

  • Step 1: Find the first term by setting n=1 n = 1 .
  • Step 2: Use the formula n3 n^3 to calculate the cube of 1.
  • Step 3: Repeat the process for the next three integers: n=2,3, n = 2, 3, and 4 4 .

Calculations:

Step 1: For n=1 n = 1 13=1 1^3 = 1 Thus, the first term is 1.

Step 2: For n=2 n = 2 23=2×2×2=8 2^3 = 2 \times 2 \times 2 = 8 Thus, the second term is 8.

Step 3: For n=3 n = 3 33=3×3×3=27 3^3 = 3 \times 3 \times 3 = 27 Thus, the third term is 27.

Step 4: For n=4 n = 4 43=4×4×4=64 4^3 = 4 \times 4 \times 4 = 64 Thus, the fourth term is 64.

Therefore, the first four terms of the series n3 n^3 are: 1,8,27, 1, 8, 27, and 64 64 .

The correct multiple-choice answer is: 1,8,27,64 1, 8, 27, 64

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Final Answer

1,8,27,64

Key Points to Remember

Essential concepts to master this topic
  • Pattern: Cube each positive integer starting from n = 1
  • Calculation: For n = 3, compute 33=3×3×3=27 3^3 = 3 \times 3 \times 3 = 27
  • Check: Verify sequence grows rapidly: 1, 8, 27, 64 shows cubing pattern ✓

Common Mistakes

Avoid these frequent errors
  • Confusing cubes with squares
    Don't calculate n2 n^2 instead of n3 n^3 = getting 1,4,9,16! This gives you square numbers, not cube numbers. Always multiply the number by itself three times for cubes.

Practice Quiz

Test your knowledge with interactive questions

Look at the following set of numbers and determine if there is any property, if so, what is it?

\( 94,96,98,100,102,104 \)

FAQ

Everything you need to know about this question

What's the difference between n2 n^2 and n3 n^3 ?

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Squares use two factors: 32=3×3=9 3^2 = 3 \times 3 = 9
Cubes use three factors: 33=3×3×3=27 3^3 = 3 \times 3 \times 3 = 27

Remember: cubes always have three identical factors!

Why does 13=1 1^3 = 1 ?

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Any power of 1 equals 1! Since 13=1×1×1=1 1^3 = 1 \times 1 \times 1 = 1 , the first term is always 1 for any positive integer sequence starting with n = 1.

How do I remember which answer is correct?

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Look for the rapid growth pattern! Cube sequences grow much faster than square sequences:

  • Squares: 1, 4, 9, 16 (differences: 3, 5, 7)
  • Cubes: 1, 8, 27, 64 (differences: 7, 19, 37)

Do I always start with n = 1?

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For "first four terms" problems, yes! Unless told otherwise, start with n = 1 and work up to n = 4 to find the first four terms of the sequence.

What if I make a calculation error?

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Double-check each cube calculation step by step. For example: 43=4×4=16 4^3 = 4 \times 4 = 16 , then 16×4=64 16 \times 4 = 64 . Breaking it into steps prevents mistakes!

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