Calculate the First Four Terms of n³ Sequence: Cube Number Series

Question

For the series n3 n^3

Find the first four terms.

Video Solution

Solution Steps

00:00 Find the first four terms
00:06 Let's substitute the desired term position in the sequence formula and solve
00:23 This is the first term in the sequence
00:29 We'll use the same method to find the next terms
00:36 Let's substitute the desired term position in the sequence formula and solve
00:45 This is the second term
00:49 Let's substitute the desired term position in the sequence formula and solve
01:00 This is the third term
01:22 And this is the solution to the question

Step-by-Step Solution

To solve for the first four terms of the series n3 n^3 , we follow these steps:

  • Step 1: Find the first term by setting n=1 n = 1 .
  • Step 2: Use the formula n3 n^3 to calculate the cube of 1.
  • Step 3: Repeat the process for the next three integers: n=2,3, n = 2, 3, and 4 4 .

Calculations:

Step 1: For n=1 n = 1 13=1 1^3 = 1 Thus, the first term is 1.

Step 2: For n=2 n = 2 23=2×2×2=8 2^3 = 2 \times 2 \times 2 = 8 Thus, the second term is 8.

Step 3: For n=3 n = 3 33=3×3×3=27 3^3 = 3 \times 3 \times 3 = 27 Thus, the third term is 27.

Step 4: For n=4 n = 4 43=4×4×4=64 4^3 = 4 \times 4 \times 4 = 64 Thus, the fourth term is 64.

Therefore, the first four terms of the series n3 n^3 are: 1,8,27, 1, 8, 27, and 64 64 .

The correct multiple-choice answer is: 1,8,27,64 1, 8, 27, 64

Answer

1,8,27,64