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To solve this problem, we will perform vertical addition of the two numbers:
We have: \begin{array}{c@{}c@{}c@{}c@{}c@{}c} & & & & & \\ & 7 & 8 & 1 & 5 & 6 \\ + & 1 & 9 & 7 & 6 & 3 \\ \hline \end{array}
Let's add the numbers column by column from right to left:
Thus, the sum is .
The solution to the problem is , which matches choice 97919
97919
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When two digits add up to 10 or more, you write the ones digit and carry the tens digit to the next column. For example, , so write 1 and carry 1.
We start from the ones place because carrying moves from right to left. If we started from the left, we couldn't handle carries properly!
Always carry the tens digit only. If , write down 7 and carry the 1. The carried digit is always smaller!
Try adding the numbers in a different order or use a calculator to verify. You can also estimate: , so 97919 makes sense!
If one number is shorter, treat the missing digits as 0. For example, adding 156 + 78 means the hundreds place is .
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