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To solve this problem, we'll follow these steps:
We will align the numbers by their place values:
Add the digits in the ones place: .
Since 10 is greater than 9, write down 0 in the ones place and carry over 1 to the tens place.
Add the digits in the tens place, including the carry-over: .
Again, write down 0 in the tens place and carry over 1 to the hundreds place.
Add the digits in the hundreds place, including the carry-over: .
Write down the entire 10 since there is no further place to carry over.
The result of the addition is 1000.
Therefore, the solution to the problem is .
1000
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
Our number system only allows one digit per place value! When 7+3=10, the '1' represents 10 ones, which equals 1 ten. So we write 0 in the ones place and carry the 1 to the tens place.
You'll get the wrong answer! In this problem, if you forget the carried 1 in the tens place, you'd get 5+4=9 instead of 5+4+1=10. Always remember to add any carried digits.
The rightmost digits should be directly above each other. Think of it like money - all the pennies line up, all the dimes line up, and so on. The 7 and 3 should be in the same column.
It's much harder! Adding right to left lets you handle carrying as you go. If you add left to right, you might need to change previous answers when carrying occurs later.
You create a new place! In this problem, when we carry 1 to the thousands place, we write the complete number 1000. The carried 1 becomes the thousands digit of our answer.
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