We have hundreds of course questions with personalized recommendations + Account 100% premium
To solve this problem, we'll perform a vertical addition of two numbers:
Add 7 (ones place of 987) to 3 (ones place of 13) to get 10. Since this sum is 10, we write down 0 in the ones place and carry over 1 to the tens place.
Add 8 (tens place of 987) to 1 (tens place of carry-over) + 1 (tens place of 13). This is 8 + 1 + 1 = 10. We write 0 in the tens place and carry over 1 to the hundreds place.
Add 9 (hundreds place of 987) to 1 (carry-over). This sum is 9 + 1 = 10. We write 0 in the hundreds place and carry over 1 to the next higher place, the thousands place.
Since the only carried-over is 1 to the thousands place, we write it as is. So the result of the addition is 1000.
Therefore, the solution to this problem is .
1000
\( \begin{aligned} &12 \\ +& \\ &~~2 \\ &\underline{\phantom{776}} & \\ \end{aligned} \)
When you add digits and get a sum of 10 or more, you write the ones digit in that column and carry the tens digit to the next column left. For example, 7+3=10, so write 0 and carry 1.
Place value alignment ensures you're adding ones to ones, tens to tens, etc. If numbers aren't lined up properly, you'll add the wrong digits together and get an incorrect answer.
That's normal! Handle each carry one column at a time. Add the original digits plus any carried amount, then decide if you need to carry again. Work systematically from right to left.
Try these methods:
Treat missing digits as zero. In this problem, 13 has no hundreds digit, so it's really 013. This makes it easier to see: 987 + 013 = 1000.
Get unlimited access to all 18 Arithmetic Operations questions, detailed video solutions, and personalized progress tracking.
Unlimited Video Solutions
Step-by-step explanations for every problem
Progress Analytics
Track your mastery across all topics
Ad-Free Learning
Focus on math without distractions
No credit card required • Cancel anytime