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To solve this problem, we'll perform a vertical addition of two numbers:
Add 7 (ones place of 987) to 3 (ones place of 13) to get 10. Since this sum is 10, we write down 0 in the ones place and carry over 1 to the tens place.
Add 8 (tens place of 987) to 1 (tens place of carry-over) + 1 (tens place of 13). This is 8 + 1 + 1 = 10. We write 0 in the tens place and carry over 1 to the hundreds place.
Add 9 (hundreds place of 987) to 1 (carry-over). This sum is 9 + 1 = 10. We write 0 in the hundreds place and carry over 1 to the next higher place, the thousands place.
Since the only carried-over is 1 to the thousands place, we write it as is. So the result of the addition is 1000.
Therefore, the solution to this problem is .
1000
\( \begin{aligned} &90 \\ +& \\ &~~9\\ &\underline{\phantom{776}} & \\ \end{aligned} \)
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