Calculate Total Building Volume: Sum of 16 Rooms with 3 Different Dimensions

Question

An architect has to design a new building.

In the building there are the following rooms:

  1. 3 rooms with heights of 4 m, lengths of 7 m and widths of 3 m.

  2. 7 rooms with heights of 9 m, lengths of 4 m and widths of 7 m.

  3. 6 rooms with heights of 11 m, lengths of 3 m and widths of 12 m.

    Calculate the total volume of the building.

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Calculate the volume for each type of room.
  • Step 2: Multiply the volume by the number of respective rooms.
  • Step 3: Sum these volumes to determine the building's total volume.

Let's proceed with the calculations:

Step 1: Calculate the volume for each type of room.
For the first type of room:

V1=4×7×3=84m3V_1 = 4 \times 7 \times 3 = 84 \, \text{m}^3

For the second type of room:

V2=9×4×7=252m3V_2 = 9 \times 4 \times 7 = 252 \, \text{m}^3

For the third type of room:

V3=11×3×12=396m3V_3 = 11 \times 3 \times 12 = 396 \, \text{m}^3

Step 2: Multiply each volume by the number of corresponding rooms.

Total volume for the first type of room:

3×84=252m33 \times 84 = 252 \, \text{m}^3

Total volume for the second type of room:

7×252=1764m37 \times 252 = 1764 \, \text{m}^3

Total volume for the third type of room:

6×396=2376m36 \times 396 = 2376 \, \text{m}^3

Step 3: Sum these results to find the total volume.

Total volume of the building:

252+1764+2376=4392m3252 + 1764 + 2376 = 4392 \, \text{m}^3

This means the total volume of the building is 4392m34392 \, \text{m}^3.

Answer

4392 m3 m^3