Compare Numbers to 4/2: Sorting Fractions, Decimals, and Percentages

Question

Organise the values below into two groups of values greater than 42 \frac{4}{2} and values less than 42 \frac{4}{2} :

1.3,12,150%,7412,0.5 1.3,\frac{1}{2},150\%,\frac{74}{12},0.5

Video Solution

Solution Steps

00:00 Decide whether smaller or larger than the given number
00:03 Let's calculate the portion
00:06 Multiply by 100 and convert to percentages
00:12 Now let's compare each number to the given number, and decide if it's larger or smaller
00:18 We can see that this number is definitely smaller than 2
00:22 This number is also smaller than 2
00:27 These percentages are smaller than 200 percent
00:32 Convert the fraction to a mixed number
00:35 Break down the whole number into remainder
00:45 Convert from whole fraction to whole number, and combine with mixed number
00:51 We can see that this number is larger than the given number
00:56 We can see that this number is smaller than 2
01:01 Now let's divide into groups, the group larger than and the group smaller than the given number
01:20 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we need to compare each given value with 42 \frac{4}{2} .

  • Calculate 42=2 \frac{4}{2} = 2 .

Now, convert all given values to decimals:

  • The value 1.3 1.3 is already in decimal form: 1.3 1.3 .
  • Convert 12 \frac{1}{2} to decimals: 0.5 0.5 .
  • Convert 150% 150\% to decimals by dividing by 100: 150100=1.5 \frac{150}{100} = 1.5 .
  • Calculate 74126.1667 \frac{74}{12} \approx 6.1667 .
  • 0.5 0.5 is already in decimal form: 0.5 0.5 .

Now, compare each value with 2 2 :

  • Values less than 2 2 : 1.3,12,150%,0.5 1.3, \frac{1}{2}, 150\%, 0.5 (i.e., 1.3,0.5,1.5,0.5 1.3, 0.5, 1.5, 0.5 ).
  • Values greater than 2 2 : 7412 \frac{74}{12} (i.e., approximately 6.1667 6.1667 ).

Therefore, the solution to the problem is:

1.3,12,150%,0.5<42 1.3, \frac{1}{2}, 150\%, 0.5 < \frac{4}{2}

7412>42 \frac{74}{12} > \frac{4}{2}

Answer

1.3,\frac{1}{2},150\%,0.5<\frac{4}{2}

\frac{74}{12}>\frac{4}{2}