Converting a Semicircular Graph to Its Algebraic Function Representation

Question

Find the corresponding algebraic representation for the function

Video Solution

Solution Steps

00:00 Choose the appropriate algebraic representation for the function
00:04 In a smiling function, the coefficient of X squared is positive
00:08 Conversely, in a sad function, the coefficient is negative
00:12 Our function is smiling, so a negative coefficient is not possible
00:19 In this case, X is not squared, so the function will be linear
00:31 When the function is linear, if you input a negative number, it stays negative
00:34 Our function is always positive, so this cannot be
00:43 The same case applies in this option
00:56 Let's check this option with a negative number
01:00 In this option, the function is always positive
01:04 And this is the solution to the question

Step-by-Step Solution

In this problem, we are tasked with identifying the algebraic representation of a function given a graphical depiction. Given the problem's indication that we are dealing with parabolas, particularly those of the form y=x2+c y = x^2 + c , we need to examine the provided graph for features typical of this family of functions.

The graph structure in the problem suggests a parabolic curve, centered symmetrically, which is indicative of the simplest unmodified parabola, y=x2 y = x^2 . The vertex likely lies at the origin, and the parabola opens upwards, a key characteristic of the function y=x2 y = x^2 when the coefficient of x2 x^2 is positive and equal to 1.

Upon reviewing the multiple-choice options, the expression that corresponds to this graph is:

  • Option 1: y=x2 y = x^2

Therefore, the algebraic representation that corresponds to the function is y=x2 y = x^2 .

Answer

y=x2 y=x^2