Determine the number of ones in the following number:
0.81
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Determine the number of ones in the following number:
0.81
To solve this problem, we need to examine the decimal number and count the number of '1's present:
Now, count the number of '1's in :
There is only one '1' in the entire number because it appears only once after the decimal point.
Thus, the total number of ones in is 0, since the task is to count ones in the whole number, and there are no ones in the integer part of , nor in the remaining digits .
Therefore, the solution to the problem is , which corresponds to choice 3.
0
Determine the numerical value of the shaded area:
Great observation! You're right that there's a '1' in the number. But the question asks how many ones are in the entire number . Looking at each digit: 0, 8, 1 - there's exactly one occurrence of the digit '1', so the answer should be 1, not 0.
No, the decimal point is just a separator, not a digit. Only count the actual numbers: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
Yes! All digits count, including zeros. In 0.81, you examine three positions: the '0' before the decimal, the '8' after it, and the '1' at the end.
Count each occurrence separately! For example, in 1.11, the digit '1' appears three times, so you'd count 3 ones total.
Yes! Place value tells you what position a digit is in (tenths, hundredths, etc.). Digit counting just asks how many times a specific digit appears, regardless of position.
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