Craft an Algebraic Expression Using Parameters: a = -1, b = 1, c = 2

Quadratic Functions with Given Parameters

Create an algebraic expression based on the following parameters:

a=1,b=1,c=2 a=-1,b=1,c=2

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Convert the parameters to a quadratic function
00:03 We'll use the formula to represent a quadratic equation
00:09 Connect the parameter to the corresponding variable according to the formula
00:25 Write the function in its reduced form
00:34 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Create an algebraic expression based on the following parameters:

a=1,b=1,c=2 a=-1,b=1,c=2

2

Step-by-step solution

First, we review our quadratic function formula: y=ax2+bx+c y = ax^2 + bx + c .

To create the expression:

  • We substitute a=1 a = -1 , b=1 b = 1 , and c=2 c = 2 into the expression.
  • This results in: y=1x2+1x+2 y = -1 \cdot x^2 + 1 \cdot x + 2 .
  • Simplifying, we have: y=x2+x+2 y = -x^2 + x + 2 .

Thus, the algebraic expression is: x2+x+2 -x^2 + x + 2 .

3

Final Answer

x2+x+2 -x^2+x+2

Key Points to Remember

Essential concepts to master this topic
  • Standard Form: Use the general formula y=ax2+bx+c y = ax^2 + bx + c
  • Substitution: Replace a = -1, b = 1, c = 2 into the formula
  • Verification: Check that x2+x+2 -x^2 + x + 2 matches the coefficients ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting negative signs when substituting parameters
    Don't write x2+x+2 x^2 + x + 2 when a = -1 = wrong leading coefficient! This ignores the negative value of parameter a. Always carefully substitute each parameter with its correct sign into ax2+bx+c ax^2 + bx + c .

Practice Quiz

Test your knowledge with interactive questions

What is the value of the coefficient \( b \) in the equation below?

\( 3x^2+8x-5 \)

FAQ

Everything you need to know about this question

What does each parameter represent in the quadratic function?

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In y=ax2+bx+c y = ax^2 + bx + c , a is the coefficient of x2 x^2 , b is the coefficient of x x , and c is the constant term.

Why is the answer x2+x+2 -x^2 + x + 2 and not x2+x+2 x^2 + x + 2 ?

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Because a = -1, not +1! The negative sign is crucial. When we substitute a = -1, we get (1)x2=x2 (-1) \cdot x^2 = -x^2 .

Do I need to write the 1 in front of x?

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No, 1x 1 \cdot x is simply written as x x . The coefficient 1 is implied and doesn't need to be written explicitly.

What if one of the parameters was 0?

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If a = 0, it's not quadratic anymore (it becomes linear). If b = 0, you get ax2+c ax^2 + c . If c = 0, you get ax2+bx ax^2 + bx .

How do I check my work?

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Verify that each term matches: the x2 x^2 coefficient should be a, the x x coefficient should be b, and the constant should be c.

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