Decompose the Expression 5x^2+9x+4 into Trinomials

Question

Decompose the following expression into trinomials

5x2+9x+4 5x^2+9x+4

Video Solution

Solution Steps

00:00 Break down the trinomial
00:03 Take out the common factor from parentheses
00:17 Reduce what's possible
00:23 Identify the coefficients
00:33 Use the roots formula to find possible solutions
00:42 Substitute appropriate values and solve to find the solutions
00:57 Calculate the squares and products
01:14 Find the 2 possible solutions (addition and subtraction)
01:17 These are the solutions, with them we'll reconstruct the trinomial
01:21 Find what zeroes each solution
01:27 These will be the factors of the trinomial
01:46 Substitute this trinomial back into the equation
01:54 And this is the solution to the problem

Step-by-Step Solution

To solve the problem of factoring the quadratic expression 5x2+9x+45x^2 + 9x + 4, we can use the decomposition method:

  • Step 1: Identify a=5a = 5, b=9b = 9, and c=4c = 4. Calculate the product ac=54=20a \cdot c = 5 \cdot 4 = 20.
  • Step 2: We need two numbers whose product is 20 and whose sum is 9. The numbers 5 and 4 satisfy this condition because 5×4=205\times4=20 and 5+4=95+4=9.
  • Step 3: Decompose the middle term using these numbers: 5x2+5x+4x+45x^2 + 5x + 4x + 4.
  • Step 4: Group the terms: (5x2+5x)+(4x+4)(5x^2 + 5x) + (4x + 4).
  • Step 5: Factor each group: 5x(x+1)+4(x+1)5x(x + 1) + 4(x + 1).
  • Step 6: Use the distributive property to factor out the common binomial: (5x+4)(x+1)(5x + 4)(x + 1).

Therefore, the factorization of the expression 5x2+9x+45x^2 + 9x + 4 is (5x+4)(x+1) (5x+4)(x+1) .

Answer

(5x+4)(x+1) (5x+4)(x+1)