Solve for 'a' in the Quadratic Equation: 4x² = -4x + 16

What is the value of $a$ in the equation $4x^2=-4x+16$?

To solve the problem, we need to express the given equation $4x^2 = -4x + 16$ in the standard quadratic form $ax^2 + bx + c = 0$.

Let's perform the necessary transformations:
Rearrange the equation:

• Start with: $4x^2 = -4x + 16$.
• Move all terms to one side to set the equation to zero:
  $4x^2 + 4x - 16 = 0$.

We now have the standard quadratic form:
$ax^2 + bx + c = 0$

In the equation $4x^2 + 4x - 16 = 0$, the coefficient of $x^2$ is 4.

Thus, the value of $a$ is $\boxed{4}$.