Determine the Axis of Symmetry for 3x^2 + 6x - 6

To find the axis of symmetry for the quadratic function $f(x) = 3x^2 + 6x - 6$, we begin by identifying the coefficients in the general form of a quadratic equation: $ax^2 + bx + c$. Here, $a = 3$, $b = 6$, and $c = -6$.

The formula for the axis of symmetry of a quadratic function is:

$x = -\frac{b}{2a}$.

Substituting the given values into the formula, we have:

$x = -\frac{6}{2 \cdot 3}$.

Calculating the above expression, we get:

$x = -\frac{6}{6} = -1$.

Thus, the axis of symmetry for this quadratic function is $x = -1$.

Therefore, the solution to the problem is $x = -1$.