Determine the Axis of Symmetry for 3x^2 + 6x - 6

Calculate the axis of symmetry of the quadratic function below:

f(x)=3x2+6x6 f(x)=3x^2+6x-6

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Step-by-step video solution

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00:00 Find the axis of symmetry for the function
00:03 The axis of symmetry is the X value at the vertex point
00:06 The point where if you fold the parabola in half, both halves are identical
00:09 Let's look at the function's coefficients
00:18 We'll use the formula to calculate the vertex point
00:24 We'll substitute appropriate values according to the given data and solve for X point
00:38 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Calculate the axis of symmetry of the quadratic function below:

f(x)=3x2+6x6 f(x)=3x^2+6x-6

2

Step-by-step solution

To find the axis of symmetry for the quadratic function f(x)=3x2+6x6 f(x) = 3x^2 + 6x - 6 , we begin by identifying the coefficients in the general form of a quadratic equation: ax2+bx+c ax^2 + bx + c . Here, a=3 a = 3 , b=6 b = 6 , and c=6 c = -6 .

The formula for the axis of symmetry of a quadratic function is:

x=b2a x = -\frac{b}{2a} .

Substituting the given values into the formula, we have:

x=623 x = -\frac{6}{2 \cdot 3} .

Calculating the above expression, we get:

x=66=1 x = -\frac{6}{6} = -1 .

Thus, the axis of symmetry for this quadratic function is x=1 x = -1 .

Therefore, the solution to the problem is x=1 x = -1 .

3

Final Answer

x=1 x=-1

Practice Quiz

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Given the expression of the quadratic function

The symmetrical axis of the expression must be found.

\( f(x)=7x^2 \)

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