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To solve the problem, we will perform long division of 34211 by 3:
After completing the division, the quotient is and the remainder is .
Therefore, the solution to the problem is with a remainder of .
with a remainder of 2
Writing 0 as a placeholder keeps each digit in its correct position! Without it, your answer shifts left and becomes wrong. In this problem, when 1÷3=0, we must write the 0.
When the dividend digit is smaller than the divisor, write 0 in the quotient and bring down the next digit. For example, 1÷3=0 with remainder 1.
You're finished when you've brought down all digits from the original number. The final remainder (if any) is what's left over after the last step.
Yes! Multiply your quotient by the divisor and add the remainder. If you get the original number, your division is correct!
The remainder is the amount left over that can't be divided evenly. In , we get 11403 with 2 left over.
We start with the largest place values first (thousands, hundreds, etc.) to build the answer systematically, just like how we read numbers from left to right!
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