Divide 34211 by 3: Step-by-Step Long Division Problem

Long Division with Five-Digit Numbers

334211

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:03 Let's start by dividing the leftmost digit in the dividend
00:07 Write the result above
00:10 Now multiply the result by the divisor
00:13 Subtract the product from the number
00:16 Now bring down the next digit and use the same steps
00:19 Divide
00:22 Write the result without remainder above, paying attention to position
00:25 Multiply the result and subtract
00:30 Now bring down the next digit and use the same steps
00:33 Divide
00:37 Write the result without remainder above, paying attention to position
00:41 Multiply the result and subtract
00:44 Now bring down the next digit and use the same steps
00:48 Divide
00:51 Write the result without remainder above, paying attention to position
00:54 Multiply the result and subtract
00:58 Now bring down the next digit and use the same steps
01:02 Divide
01:05 Write the result without remainder above, paying attention to position
01:09 Multiply the result and subtract
01:14 We got a remainder of 2
01:21 And this is the solution to the problem

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

334211

2

Step-by-step solution

To solve the problem, we will perform long division of 34211 by 3:

  • Step 1: Divide the first digit of 34211, which is 3, by 3. 3÷3=13 \div 3 = 1. Write 1 on top.
  • Step 2: Subtract 1×3=31 \times 3 = 3 from the first 3, getting a remainder of 0. Now bring down the next digit, 4, making it 04.
  • Step 3: Divide 04 by 3. 4÷3=14 \div 3 = 1. Write 1 on top.
  • Step 4: Subtract 1×3=31 \times 3 = 3 from 4, getting a remainder of 1. Bring down the next digit, 2, making it 12.
  • Step 5: Divide 12 by 3. 12÷3=412 \div 3 = 4. Write 4 on top.
  • Step 6: Subtract 4×3=124 \times 3 = 12 from 12, getting a remainder of 0. Bring down the next digit, 1, making it 01.
  • Step 7: Divide 01 by 3. 1÷3=01 \div 3 = 0. Write 0 on top.
  • Step 8: Subtract 0×3=00 \times 3 = 0 from 1, getting a remainder of 1. Bring down the final digit, 1, making it 11.
  • Step 9: Divide 11 by 3. 11÷3=311 \div 3 = 3. Write 3 on top.
  • Step 10: Subtract 3×3=93 \times 3 = 9 from 11 to get a remainder of 2.

After completing the division, the quotient is 1140311403 and the remainder is 22.

Therefore, the solution to the problem is 11403\mathbf{11403} with a remainder of 2\mathbf{2}.

3

Final Answer

11403 11403 with a remainder of 2

Key Points to Remember

Essential concepts to master this topic
  • Rule: Divide each digit group systematically from left to right
  • Technique: Bring down next digit when remainder is less than divisor: 1→12→0
  • Check: Multiply quotient by divisor and add remainder: 11403×3+2=34211 ✓

Common Mistakes

Avoid these frequent errors
  • Forgetting to write zero placeholders in quotient
    Don't skip writing 0 when a digit can't be divided = missing place values! This shifts all following digits one position left, giving completely wrong answers. Always write 0 in the quotient when the dividend digit is smaller than the divisor.

Practice Quiz

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216

FAQ

Everything you need to know about this question

Why do I need to write 0 in the middle of my answer?

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Writing 0 as a placeholder keeps each digit in its correct position! Without it, your answer shifts left and becomes wrong. In this problem, when 1÷3=0, we must write the 0.

What if I can't divide a number by the divisor?

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When the dividend digit is smaller than the divisor, write 0 in the quotient and bring down the next digit. For example, 1÷3=0 with remainder 1.

How do I know when I'm done with the division?

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You're finished when you've brought down all digits from the original number. The final remainder (if any) is what's left over after the last step.

Can I check my long division answer?

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Yes! Multiply your quotient by the divisor and add the remainder. If you get the original number, your division is correct!

What does 'remainder' mean in division?

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The remainder is the amount left over that can't be divided evenly. In 34211÷3 34211 ÷ 3 , we get 11403 with 2 left over.

Why does long division work from left to right?

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We start with the largest place values first (thousands, hundreds, etc.) to build the answer systematically, just like how we read numbers from left to right!

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