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To solve this problem, we'll follow the steps of long division to divide 9120 by 3:
Step 1: Divide the thousands place:
- 3 goes into 9 three times. Multiply 3 by 3 to get 9. Subtract 9 from 9 to get 0.
Step 2: Bring down the next digit (1):
- 3 goes into 1 zero times. Multiply 3 by 0 to get 0. Subtract 0 from 1 to keep 1.
Step 3: Bring down the next digit (2):
- Now divide 12 by 3, which equals 4. Multiply 3 by 4 to get 12. Subtract 12 from 12 to get 0.
Step 4: Finally, bring down the last digit (0):
- 3 goes into 0 zero times. Thus, the result of this step is 0.
Therefore, the quotient when 9120 is divided by 3 is .
When a single digit like 1 is smaller than the divisor 3, write 0 in the quotient and combine it with the next digit. So 1 becomes 12 when you bring down the next digit.
Each digit in your quotient goes directly above the corresponding digit in the dividend. The first digit of 3040 goes above the 9 in 9120.
In this problem, 9120 divides evenly by 3 with no remainder. If you do get a remainder, write it as "R" followed by the number, like 1021 R 1.
Bringing down digits one at a time helps you work with smaller, manageable numbers. It's much easier to divide 12 by 3 than to tackle 9120 all at once!
Multiply your answer by the original divisor: . If you get back to 9120, your division is correct!
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