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To solve this problem using long division, follow these steps:
The dividend is 974, and the divisor is 5.
Take the first digit of the dividend, which is 9. Divide 9 by 5 to get 1 because 5 goes into 9 once.
Multiply the divisor (5) by the quotient digit (1): .
Subtract this from 9 to get a remainder of 4: .
Bring down the next digit from the dividend (7), making the new number 47.
Now divide 47 by 5. 5 goes into 47 nine times, so the next digit of the quotient is 9.
Multiply the divisor (5) by this quotient digit (9): .
Subtract this from 47 to get a remainder of 2: .
Bring down the final digit (4), making the new number 24.
Finally, divide 24 by 5. 5 goes into 24 four times. The last digit of the quotient is 4.
Multiply the divisor (5) by 4: .
Subtract this from 24 to get a final remainder of 4: .
Thus, the result of 974 divided by 5 is a quotient of with a remainder of .
The correct choice is therefore Choice 4: with a remainder of .
with a remainder of 4
If 5 won't go into 9, you'd take the first two digits (like 97) and divide by 5. The quotient would then be a 2-digit number instead of 3-digit.
Stop when you've brought down all digits from the original number (974). The final remainder should be smaller than the divisor - here, remainder 4 is less than divisor 5.
Yes! Use the division relationship: Dividend = Quotient × Divisor + Remainder. So should be true.
Double-check your subtraction at each step! The most common error is subtracting incorrectly when bringing down digits. Work slowly and verify each calculation.
Because , which is the largest multiple of 5 that doesn't exceed 47. The next multiple would be too big!
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