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To solve this problem, we'll follow these steps:
Now, let's work through each step:
Step 1: We start by setting up the division as follows: place outside the division symbol and inside.
Step 2: Perform the division:
The quotient is and the remainder is .
Therefore, the solution to the problem is with a remainder of .
with a remainder of 5
Write 0 in that position of the quotient and bring down the next digit. For example, since 6 doesn't go into 1, we write 0 and bring down the 7 to make 17.
You're done when you've brought down all digits from the dividend and performed the final division step. The last number left is your remainder.
The remainder is what's left over after division. In , we can make 102 complete groups of 6, with 5 left over.
Yes! Use this formula: quotient × divisor + remainder = original dividend. For our problem: ✓
We start from the left because that's where the largest place values are (hundreds, then tens, then ones). This ensures we build our quotient in the correct order.
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