Will a number divisible by 3 necessarily be divisible by 9?
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Will a number divisible by 3 necessarily be divisible by 9?
To solve this problem, we need to understand the divisibility rules for 3 and 9:
Let's evaluate whether a number divisible by 3 is necessarily divisible by 9:
Consider the number 12. The sum of its digits is , which is divisible by 3, so 12 is divisible by 3. However, when we check divisibility by 9, 12 is not divisible by 9 because 3 is not divisible by 9.
Now consider another number, like 18. The sum of its digits is , which is divisible by both 3 and 9. Thus, 18 is divisible by both.
These examples demonstrate that while some numbers divisible by 3 are also divisible by 9 (e.g., 18), not all are (e.g., 12).
Therefore, a number being divisible by 3 does not necessarily mean it is divisible by 9.
The correct answer is No.
No
Determine if the following number is divisible by 3:
\( 352 \)
Because 9 is stricter than 3! While 3 only needs the digit sum divisible by 3, 9 needs the digit sum divisible by 9. For example, 12 has digit sum 3, which works for 3 but not for 9.
Absolutely! Try 6, 15, 21, 24, 30. All have digit sums divisible by 3 but not by 9. For instance: for 21, and 3 ÷ 3 = 1 but 3 ÷ 9 doesn't work!
When its digit sum is divisible by 9! Since 9 is a multiple of 3, any number divisible by 9 is automatically divisible by 3. Examples: 18, 27, 36, 45.
Think of it as levels: divisible by 3 is level 1, divisible by 9 is level 2. You need level 2 to get level 1, but level 1 doesn't guarantee level 2!
Pick simple numbers! Start with 12: . Since 3 ÷ 3 = 1 (works) but 3 ÷ 9 doesn't work, you've found your counterexample!
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