Evaluate the Expression: 10-(-2)-3×4-(-4) Using Order of Operations

Question

$10-(-2)-3?4-(-4)$

00:00 Choose the appropriate sign

00:03 Negative times negative is always positive

00:07 Let's open the parentheses

00:16 Let's calculate one operation

00:24 Let's find point (12) on the axis

00:27 Positive times negative is always negative

00:31 Let's take 3 jumps left (to the negative side) on the axis

00:41 This is the solution for the left side, now let's calculate the right side

00:45 Negative times negative is always positive

00:49 Let's open the parentheses

00:53 This is the solution for the right side

01:01 And this is the solution to the question

First we need to remember the following laws:

$-(-x)=+x$

$+(-x)=-x$

We'll solve the left side first.

Let's rewrite the expression in the appropriate form:

$10+2-3=$

Next, we'll solve the exercise from left to right:

$10+2=12$

$12-3=9$

Now let's solve the right-hand side, using the laws we reminded ourselves of earlier.

We'll then rewrite the expression in the appropriate form and solve:

$4+4=8$

Since the left-hand side is larger, the appropriate sign will be:

$9 > 8$

$>$