Evaluate the Expression: 10-(-2)-3×4-(-4) Using Order of Operations

10(2)3?4(4) 10-(-2)-3?4-(-4)

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Choose the appropriate sign
00:03 Negative times negative is always positive
00:07 Let's open the parentheses
00:16 Let's calculate one operation
00:24 Let's find point (12) on the axis
00:27 Positive times negative is always negative
00:31 Let's take 3 jumps left (to the negative side) on the axis
00:41 This is the solution for the left side, now let's calculate the right side
00:45 Negative times negative is always positive
00:49 Let's open the parentheses
00:53 This is the solution for the right side
01:01 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

10(2)3?4(4) 10-(-2)-3?4-(-4)

2

Step-by-step solution

First we need to remember the following laws:

(x)=+x -(-x)=+x

+(x)=x +(-x)=-x

We'll solve the left side first.

Let's rewrite the expression in the appropriate form:

10+23= 10+2-3=

Next, we'll solve the exercise from left to right:

10+2=12 10+2=12

123=9 12-3=9

Now let's solve the right-hand side, using the laws we reminded ourselves of earlier.

We'll then rewrite the expression in the appropriate form and solve:

4+4=8 4+4=8

Since the left-hand side is larger, the appropriate sign will be:

9>8 9 > 8

3

Final Answer

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Practice Quiz

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What will be the sign of the result of the next exercise?

\( (-2)\cdot(-4)= \)

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