Evaluate the Sequence: Finding the First Term in 6n² - 1

Sequence Evaluation with Quadratic Formulas

A sequence has the rule 6n21 6n^2-1 .

What is the first term?

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the first term
00:03 We'll substitute the appropriate term's position in the formula and solve
00:17 Always solve exponents first
00:23 Always solve multiplication and division before addition and subtraction
00:28 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

A sequence has the rule 6n21 6n^2-1 .

What is the first term?

2

Step-by-step solution

To solve this problem, we'll calculate the first term of the sequence defined by the rule 6n21 6n^2 - 1 :

  • Step 1: Identify the position for the first term. By convention, this position is n=1 n = 1 .
  • Step 2: Substitute n=1 n = 1 into the formula 6n21 6n^2 - 1 :

Substitution and calculation:

For n=1 n = 1 , the expression becomes 6(1)21 6(1)^2 - 1 .

Calculate 6(1)2 6(1)^2 : 6×1=6 6 \times 1 = 6 .

Subtract 1 from 6: 61=5 6 - 1 = 5 .

Therefore, the first term of the sequence is 5 \boxed{5} .

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Final Answer

5

Key Points to Remember

Essential concepts to master this topic
  • Rule: First term occurs when n = 1 in any sequence formula
  • Technique: Substitute n = 1: 6(1)21=61=5 6(1)^2 - 1 = 6 - 1 = 5
  • Check: Verify by calculating second term: 6(2)21=23 6(2)^2 - 1 = 23

Common Mistakes

Avoid these frequent errors
  • Starting with n = 0 instead of n = 1
    Don't use n = 0 to find the first term = gives 6(0)² - 1 = -1! This assumes sequences start at position zero, but by convention the first term corresponds to n = 1. Always substitute n = 1 for the first term of any sequence.

Practice Quiz

Test your knowledge with interactive questions

12 ☐ 10 ☐ 8 7 6 5 4 3 2 1

Which numbers are missing from the sequence so that the sequence has a term-to-term rule?

FAQ

Everything you need to know about this question

Why do we use n = 1 for the first term instead of n = 0?

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By mathematical convention, sequences typically start with the first term at position n = 1. This matches how we naturally count: 1st, 2nd, 3rd terms, not 0th, 1st, 2nd terms.

What if the problem asked for the 3rd term instead?

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Simply substitute n = 3 into the formula! For 6n21 6n^2 - 1 , you'd get 6(3)21=6(9)1=53 6(3)^2 - 1 = 6(9) - 1 = 53 .

How do I know this formula gives a sequence and not just one number?

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The variable n tells you it's a sequence! Each different value of n (1, 2, 3, 4...) produces a different term in the sequence.

Can sequence formulas have negative terms?

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Absolutely! Depending on the formula and position n, terms can be positive, negative, or zero. Always calculate exactly what the formula gives you.

Do I need to simplify 6(1)² before subtracting 1?

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Yes! Follow the order of operations: first calculate the exponent (1² = 1), then multiply (6 × 1 = 6), then subtract (6 - 1 = 5).

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