Evaluate y = x² Function: Finding Point at x = 11

Given the function:

y=x2 y=x^2

Is there a point for ? x=11 x=11 ?

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Step-by-step video solution

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00:00 Does the point exist?
00:03 Let's substitute appropriate values according to the given data, and solve to find the point
00:11 Let's calculate the exponent
00:14 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Given the function:

y=x2 y=x^2

Is there a point for ? x=11 x=11 ?

2

Step-by-step solution

To solve this problem, we will calculate the value of y y for the given function y=x2 y = x^2 when x=11 x = 11 .

Here are the steps to find the solution:

  • Step 1: Substitute x=11 x = 11 into the function equation.
  • Step 2: Calculate y=112 y = 11^2 .

Let's work through these steps:

Step 1: By substituting x=11 x = 11 , the function becomes y=112 y = 11^2 .

Step 2: Calculate the value:

112=11×11=121 11^2 = 11 \times 11 = 121

Therefore, for x=11 x = 11 , the value of y y is 121 121 , meaning the point (11,121)(11, 121) does exist on the function y=x2 y = x^2 .

The correct answer from the given choices is y=121 y = 121 , which corresponds to choice id "3".

3

Final Answer

y=121 y=121

Practice Quiz

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What is the value of y for the function?

\( y=x^2 \)

of the point \( x=2 \)?

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