Expand the Expression: (2y-3)(y-4) Using Binomial Multiplication

Binomial Multiplication with Negative Terms

Solve the exercise:

(2y3)(y4)= (2y-3)(y-4)=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Solve
00:04 Open parentheses properly, multiply each factor by each factor
00:27 Calculate the products
00:52 Positive times negative always equals negative
01:01 Collect terms
01:07 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the exercise:

(2y3)(y4)= (2y-3)(y-4)=

2

Step-by-step solution

To solve the algebraic expression (2y3)(y4)(2y-3)(y-4), we will apply the distributive property, also known as the FOIL method for binomials. This involves multiplying each term in the first binomial by each term in the second binomial.

  • Step 1: Multiply the first terms: 2y×y=2y2 2y \times y = 2y^2 .
  • Step 2: Multiply the outer terms: 2y×4=8y 2y \times -4 = -8y .
  • Step 3: Multiply the inner terms: 3×y=3y -3 \times y = -3y .
  • Step 4: Multiply the last terms: 3×4=12 -3 \times -4 = 12 .

Next, we combine all these results: 2y28y3y+12 2y^2 - 8y - 3y + 12 .

Then, we combine the like terms 8y-8y and 3y-3y to get 11y-11y.

Therefore, the expanded expression is 2y211y+12 2y^2 - 11y + 12 .

This matches choice (3): 2y211y+12 2y^2 - 11y + 12 .

Thus, the solution to the problem is 2y211y+12 2y^2 - 11y + 12 .

3

Final Answer

2y211y+12 2y^2-11y+12

Key Points to Remember

Essential concepts to master this topic
  • FOIL Method: First, Outer, Inner, Last terms multiply systematically
  • Technique: 2y×(4)=8y 2y \times (-4) = -8y and (3)×y=3y (-3) \times y = -3y
  • Check: Combine like terms: 8y+(3y)=11y -8y + (-3y) = -11y

Common Mistakes

Avoid these frequent errors
  • Sign errors when multiplying negative terms
    Don't forget that (-3) × (-4) = +12, not -12! Students often lose track of negative signs during multiplication. Always track each sign carefully: negative × negative = positive, negative × positive = negative.

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

Why do I keep getting the wrong sign on my constant term?

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This happens when you forget that negative times negative equals positive! In (3)×(4) (-3) \times (-4) , both numbers are negative, so the result is positive 12, not negative 12.

What's the easiest way to remember FOIL?

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First terms, Outer terms, Inner terms, Last terms. For (2y3)(y4) (2y-3)(y-4) : First = 2yy 2y \cdot y , Outer = 2y(4) 2y \cdot (-4) , Inner = (3)y (-3) \cdot y , Last = (3)(4) (-3) \cdot (-4) .

How do I combine the middle terms correctly?

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Add the coefficients of like terms: 8y+(3y)=8y3y=11y -8y + (-3y) = -8y - 3y = -11y . Remember that adding a negative is the same as subtracting!

Can I check my answer by substituting a value?

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Yes! Pick any value for y (like y = 1). Check: (2(1)3)(14)=(1)(3)=3 (2(1)-3)(1-4) = (-1)(-3) = 3 and 2(1)211(1)+12=211+12=3 2(1)^2-11(1)+12 = 2-11+12 = 3 . Both equal 3 ✓

What if I get confused with all the negative signs?

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Write each step clearly and use parentheses! For example: 2y2+(8y)+(3y)+12 2y^2 + (-8y) + (-3y) + 12 . This makes it easier to see that you're adding negative terms.

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