Expand the Expression: (3x-1)(x+2) Using Distribution Method

Solve the exercise:

(3x−1)(x+2)= (3x-1)(x+2)=

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:07 Let's solve this problem together.
00:11 First, open the parentheses and multiply each part carefully.
00:33 Now, let's calculate these products step by step.
01:01 Remember, a positive times a negative is always negative.
01:12 Next, collect like terms together.
01:17 Great job! That's how we find the solution to this question.

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Solve the exercise:

(3x−1)(x+2)= (3x-1)(x+2)=

2

Step-by-step solution

To solve this problem, we'll apply the distributive property to expand the expression (3x−1)(x+2)(3x-1)(x+2). Below are the steps:

  • Step 1: Distribute each term in the first binomial to each term in the second binomial:

3x(x)+3x(2)+(−1)(x)+(−1)(2)3x(x) + 3x(2) + (-1)(x) + (-1)(2)

  • Step 2: Calculate each term:

3x2+6x−x−23x^2 + 6x - x - 2

  • Step 3: Combine like terms:

3x2+(6x−x)−2=3x2+5x−23x^2 + (6x - x) - 2 = 3x^2 + 5x - 2

Thus, the expanded expression is 3x2+5x−23x^2 + 5x - 2.

The correct answer choice is 3x2+5x−23x^2 + 5x - 2, corresponding to choice id="4".

3

Final Answer

3x2+5x−2 3x^2+5x-2

Practice Quiz

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It is possible to use the distributive property to simplify the expression below?

What is its simplified form?

\( (ab)(c d) \)

\( \)

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