Find Coefficients in the Quadratic Equation: 5x² + 6x - 8 = 0

Question

a = coefficient of x²

b = coefficient of x

c = coefficient of the independent number

Identifies a,b,c

5x2+6x8=0 5x^2+6x-8=0

Video Solution

Solution Steps

00:00 Here are the coefficients
00:03 The coefficient of X squared is A
00:06 The coefficient of X is B
00:09 And the constant term is C
00:12 And this is the solution to the question

Step-by-Step Solution

To identify the coefficients from the quadratic equation 5x2+6x8=0 5x^2 + 6x - 8 = 0 , follow these steps:

  • Standard Form of Quadratic Equation: Compare 5x2+6x85x^2 + 6x - 8 with the standard form ax2+bx+c=0ax^2 + bx + c = 0.
  • Identify aa, bb, and cc:
    • a=5 a = 5 : The coefficient of x2x^2.
    • b=6 b = 6 : The coefficient of xx.
    • c=8 c = -8 : The constant term (independent of xx).

Therefore, from the equation 5x2+6x8=0 5x^2 + 6x - 8 = 0 , the coefficients are identified as a=5 a=5 , b=6 b=6 , and c=8 c=-8 .

Comparing with choices, we find that choice 2 is correct: a=5 a=5 , b=6 b=6 , c=8 c=-8 .

Thus, the coefficients are identified as a=5 a=5 , b=6 b=6 , c=8 c=-8 .

Answer

a=5 a=5 b=6 b=6 c=8 c=-8