Find Coefficients in y=6+3x: Linear Equation Analysis

Quadratic Coefficients with Linear Equations

Identify the coefficients based on the following equation

y=6+3x y=6+3x

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:04 Let's find the function coefficients together.
00:08 We will use a formula to represent a quadratic equation.
00:17 Next, we'll arrange the equation so that it matches our formula.
00:39 Then, we'll separate the variable from its coefficient.
00:58 Now, we compare the formula with our equation to find the coefficients.
01:03 And that's how we solve this problem!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Identify the coefficients based on the following equation

y=6+3x y=6+3x

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Identify the given equation and its form.
  • Step 2: Compare it with the standard quadratic equation y=ax2+bx+c y = ax^2 + bx + c .
  • Step 3: Determine the values of a a , b b , and c c .
  • Step 4: Choose the correct multiple-choice answer based on these values.

Now, let's work through each step:
Step 1: The given equation is y=6+3x y = 6 + 3x . This equation is a linear equation of the form y=mx+c y = mx + c .
Step 2: We compare it with the quadratic form y=ax2+bx+c y = ax^2 + bx + c .
Step 3: Notice there is no x2 x^2 term in the given equation, which means a=0 a = 0 . The term involving x x is 3x 3x , which means b=3 b = 3 . The constant term is 6 6 , so c=6 c = 6 .
Step 4: Based on the identified values a=0 a = 0 , b=3 b = 3 , and c=6 c = 6 , the correct choice from the multiple-choice answers provided is choice 1: a=0,b=3,c=6 a=0,b=3,c=6 .

Therefore, the solution to the problem is a=0,b=3,c=6 a=0,b=3,c=6 .

3

Final Answer

a=0,b=3,c=6 a=0,b=3,c=6

Key Points to Remember

Essential concepts to master this topic
  • Standard Form: Compare given equation to ax2+bx+c ax^2 + bx + c
  • Missing Terms: No x2 x^2 term means a = 0
  • Verification: Rewrite as y=0x2+3x+6 y = 0x^2 + 3x + 6 to confirm coefficients ✓

Common Mistakes

Avoid these frequent errors
  • Confusing coefficient positions when comparing forms
    Don't assume b = 6 because 6 comes first = wrong coefficient assignment! The position in the original equation doesn't match the standard form positions. Always rearrange to match ax2+bx+c ax^2 + bx + c exactly.

Practice Quiz

Test your knowledge with interactive questions

What is the value of the coefficient \( c \) in the equation below?

\( 4x^2+9x-2 \)

FAQ

Everything you need to know about this question

Why is a = 0 when there's no x² term?

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In the standard quadratic form y=ax2+bx+c y = ax^2 + bx + c , every coefficient must have a value. When the x2 x^2 term is missing, it means the coefficient is 0, not that it doesn't exist!

How do I identify b and c in y = 6 + 3x?

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First, rearrange to standard order: y=3x+6 y = 3x + 6 . Now you can see that b = 3 (coefficient of x) and c = 6 (constant term).

What if the equation was written as y = 3x + 6 instead?

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The coefficients would be exactly the same! The order of terms doesn't change their values: a = 0, b = 3, c = 6 regardless of whether it's written as y=6+3x y = 6 + 3x or y=3x+6 y = 3x + 6 .

Is this really a quadratic equation if a = 0?

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Actually, when a = 0, it becomes a linear equation! But the question asks us to identify coefficients using the quadratic format, so we still use ax2+bx+c ax^2 + bx + c with a = 0.

How can I double-check my coefficient identification?

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Write out the full form: y=0x2+3x+6 y = 0x^2 + 3x + 6 . This should match your original equation when you simplify (since 0x2=0 0x^2 = 0 ).

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