Find Equivalent Expressions for (x+y)²: Perfect Square Expansion

Perfect Square Binomials with Middle Term Recognition

Choose the expression that has the same value as the following:

(x+y)2 (x+y)^2

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Simplify the expression
00:03 Every factor squared is actually its multiplication by itself
00:10 Let's properly open the parentheses, multiply each factor by each factor
00:33 Collect like terms
00:45 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Choose the expression that has the same value as the following:

(x+y)2 (x+y)^2

2

Step-by-step solution

To solve this problem, we will use the formula for the square of a sum, which is (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2.

Here, we identify a=x a = x and b=y b = y . Thus, our expression (x+y)2 (x+y)^2 can be expanded as follows:

(x+y)2=x2+2xy+y2 (x+y)^2 = x^2 + 2xy + y^2

Now we will match this expanded form with the given choices.

  • Choice 1: x2+y2 x^2 + y^2 - This is missing the middle term 2xy 2xy .
  • Choice 2: y2+x2+2xy y^2 + x^2 + 2xy - This matches the expanded expression.
  • Choice 3: x2+xy+y2 x^2 + xy + y^2 - The term xy xy doesn't match the required 2xy 2xy .
  • Choice 4: x22xy+y2 x^2 - 2xy + y^2 - The middle term has an incorrect sign.

Therefore, the expression that is equivalent to (x+y)2 (x+y)^2 is choice 2: y2+x2+2xy y^2 + x^2 + 2xy .

3

Final Answer

y2+x2+2xy y^2+x^2+2xy

Key Points to Remember

Essential concepts to master this topic
  • Formula: (a+b)2=a2+2ab+b2 (a+b)^2 = a^2 + 2ab + b^2 for any binomial square
  • Technique: Identify a=x a = x and b=y b = y to get x2+2xy+y2 x^2 + 2xy + y^2
  • Check: Count three terms with middle term coefficient being 2xy 2xy

Common Mistakes

Avoid these frequent errors
  • Forgetting the middle term when expanding perfect squares
    Don't expand (x+y)2 (x+y)^2 as just x2+y2 x^2 + y^2 = missing the 2xy 2xy term! This ignores the cross-multiplication that happens when FOILing (x+y)(x+y) (x+y)(x+y) . Always remember the formula produces three terms: first squared + twice the product + second squared.

Practice Quiz

Test your knowledge with interactive questions

Choose the expression that has the same value as the following:


\( (x+3)^2 \)

FAQ

Everything you need to know about this question

Why isn't (x+y)2 (x+y)^2 just x2+y2 x^2 + y^2 ?

+

Because squaring a binomial means multiplying it by itself: (x+y)(x+y) (x+y)(x+y) . When you FOIL this, you get four terms: x2+xy+yx+y2 x^2 + xy + yx + y^2 , which combines to x2+2xy+y2 x^2 + 2xy + y^2 .

How do I remember the perfect square formula?

+

Think "First, Twice, Last": First term squared + Twice the product of both terms + Last term squared. For (x+y)2 (x+y)^2 : x2 x^2 + 2xy 2xy + y2 y^2 !

What's the difference between (x+y)2 (x+y)^2 and (xy)2 (x-y)^2 ?

+

The middle term sign changes! (x+y)2=x2+2xy+y2 (x+y)^2 = x^2 + 2xy + y^2 has plus 2xy 2xy , while (xy)2=x22xy+y2 (x-y)^2 = x^2 - 2xy + y^2 has minus 2xy 2xy .

Can I rearrange the terms in the answer?

+

Yes! Addition is commutative, so x2+2xy+y2 x^2 + 2xy + y^2 , y2+x2+2xy y^2 + x^2 + 2xy , and 2xy+x2+y2 2xy + x^2 + y^2 are all equivalent expressions.

How can I check my expansion is correct?

+

Try substituting simple numbers! If x=1 x = 1 and y=2 y = 2 , then (1+2)2=9 (1+2)^2 = 9 . Your expanded form should also equal 9: 12+2(1)(2)+22=1+4+4=9 1^2 + 2(1)(2) + 2^2 = 1 + 4 + 4 = 9

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Short Multiplication Formulas questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations