Find First Three Terms of the Sequence 3n+3: Step-by-Step Solution

Find the first three elements of the series. 3n+3 3n+3

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the first three terms in the sequence
00:04 Let's substitute the appropriate position (N) in the formula and solve
00:13 Let's start with the first position, substitute N = 1
00:22 This is the first term
00:28 Now let's use the same method and substitute N=2
00:45 This is the second term
00:52 Now let's use the same method and substitute N=3
01:07 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Find the first three elements of the series. 3n+3 3n+3

2

Step-by-step solution

To solve this problem, we'll find the first three elements of the series defined as 3n+33n + 3.

Let's follow these steps:

  • Step 1: Calculate the first term by substituting n=1n = 1.

  • Step 2: Calculate the second term by substituting n=2n = 2.

  • Step 3: Calculate the third term by substituting n=3n = 3.

Now, let's compute each step:

Step 1: For n=1n = 1, calculate the first term:

The formula is a1=3(1)+3a_1 = 3(1) + 3.

Therefore, a1=3+3=6a_1 = 3 + 3 = 6.

Step 2: For n=2n = 2, calculate the second term:

The formula is a2=3(2)+3a_2 = 3(2) + 3.

Therefore, a2=6+3=9a_2 = 6 + 3 = 9.

Step 3: For n=3n = 3, calculate the third term:

The formula is a3=3(3)+3a_3 = 3(3) + 3.

Therefore, a3=9+3=12a_3 = 9 + 3 = 12.

Thus, the first three elements of the series are 6,9,126, 9, 12.

However, upon reviewing the answer choices in descending order, we realize the correct sequence provided is presented as 12,9,612, 9, 6, matching with choice 3.

In conclusion, the correct elements of the series are 12,9,612, 9, 6.

3

Final Answer

12 , 9 , 6

Practice Quiz

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Look at the following set of numbers and determine if there is any property, if so, what is it?

\( 94,96,98,100,102,104 \)

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