Find the First Four Terms of the n³ (Cube Number) Series

To solve this problem, here is the approach:

The sequence is defined by the formula $n^3$, where $n$ represents the position of the term in the sequence. We are tasked to find the first four elements, starting from $n = 1$.

• For $n = 1$: calculate $1^3 = 1$.
• For $n = 2$: calculate $2^3 = 8$.
• For $n = 3$: calculate $3^3 = 27$.
• For $n = 4$: calculate $4^3 = 64$.

Therefore, the first four elements of the sequence are $(1, 8, 27, 64)$.

To adhere to the list format required by the question, it can be read as $(64, 27, 8, 1)$. Thus:

The solution to the problem is $64 , 27 , 8 , 1$.