Find Increasing Intervals: Analyzing y = (x+6)(x-8)

To find the intervals on which the quadratic function $y = (x+6)(x-8)$ is increasing, we perform the following steps:

Step 1: Expand the quadratic to standard form:
$y = (x+6)(x-8) = x^2 - 2x - 48$

Step 2: Find the derivative of the function:
The derivative, $f'(x)$, is found by differentiating $x^2 - 2x - 48$:
$f'(x) = 2x - 2$

Step 3: Determine where the derivative is positive:
Set $f'(x) > 0$:
$2x - 2 > 0$

Solve for $x$:
$2x > 2$
$x > 1$

Therefore, the function $y = (x+6)(x-8)$ is increasing on the interval $x > 1$.

Thus, the correct answer is $x > 1$.