Find the Algebraic Expression: Analyzing Point Patterns in Geometric Sequences

In the drawing, four main structures of the series.

Choose the algebraic expression corresponding to the number of points in place ofn n

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the sequence formula
00:03 Let's count the circles in the first term
00:11 Let's substitute the first term in each equation and see if it's correct
00:29 This equation is incorrect
00:38 All these match, let's move on to check the second term
01:01 This formula matches
01:11 This formula doesn't match
01:15 And this one doesn't either
01:19 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

In the drawing, four main structures of the series.

Choose the algebraic expression corresponding to the number of points in place ofn n

2

Step-by-step solution

To find the algebraic expression representing the number of points at position n n in the series, we need to analyze any discernible pattern regarding point placement:

  • Step 1: Observe the structure pattern. Assume each structure follows a predictable order increasing by a fixed pattern.
  • Step 2: Consider simple cases — count points for the first few structures, such as at n=1 n = 1 . Assume an increment or premise is clearly visible.
  • Step 3: After identifying the arithmetic pattern, propose a general formula.

Examining different configurations (visibly similar structures increase distinctly per level), check potential arithmetic conditions, thus reflecting an identifiable arithmetic growth in complexity.

Let's apply a simple test, considering how many points appear for small n n :

If each term is characterized and growth squarely aligns with an arithmetic sequence of additional increments, we reason a formulation for a total number of points as known.

The pattern's arithmetic progression engages a dual increment formulated as 2(2n1) 2(2n-1) .

Therefore, the solution to the problem, upon careful examination, is 2(2n1) 2(2n-1) .

3

Final Answer

2(2n1) 2(2n-1)

Practice Quiz

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Is there a term-to-term rule for the sequence below?

18 , 22 , 26 , 30

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