Find the ascending area of the function
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Find the ascending area of the function
To solve this problem, we'll take the following approach step-by-step:
Now, let's work through each step:
Step 1: Differentiate the function
Given , apply the chain rule to differentiate:
We first use the substitution , so . The derivative .
Since , the derivative . Applying the chain rule, we have:
Step 2: Determine where the derivative is positive
A function is increasing when its derivative is positive, so we set the derivative greater than zero:
Solve for :
Step 3: Conclusion and multiple-choice validation
The area where the function is increasing corresponds to values of less than . According to the choices provided, the correct answer is:
, which corresponds to choice
Therefore, the solution to the problem is .
Find the intersection of the function
\( y=(x+4)^2 \)
With the Y
The derivative tells us the slope at every point! When the derivative is positive, the function has a positive slope, meaning it's going upward (increasing).
Ascending area means the same thing as increasing interval - the values of x where the function is rising or going up from left to right.
Think of it this way: positive slope = going up = increasing, so use f'(x) > 0. Negative slope = going down = decreasing, so use f'(x) < 0.
When we solve , we get . Dividing by -8 flips the inequality sign, giving us .
Absolutely! Pick any x-value in your interval (like x = -4) and check if f'(-4) > 0. If yes, your interval is correct!
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