Find the Ascending Area of y=-(2x+6)²: Domain Analysis

Function Derivatives with Increasing Intervals

Find the ascending area of the function

y=(2x+6)2 y=-(2x+6)^2

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the domain of increase of the function
00:03 We'll use shortened multiplication formulas for opening parentheses
00:11 Negative times positive is always negative
00:21 We'll look at the coefficient of X squared, negative - sad function:
00:30 We'll examine the function's coefficients
00:34 We'll use the formula to find the vertex
00:44 We'll substitute appropriate values and solve to find the vertex
00:56 This is the X value at the vertex
01:02 In a maximum parabola, the domain of increase is before the vertex
01:06 And this is the solution to the question

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Find the ascending area of the function

y=(2x+6)2 y=-(2x+6)^2

2

Step-by-step solution

To solve this problem, we'll take the following approach step-by-step:

  • Step 1: Differentiate the function.
  • Step 2: Set the derivative greater than zero and solve.
  • Step 3: Determine the correct interval for x x .

Now, let's work through each step:

Step 1: Differentiate the function
Given y=(2x+6)2 y = -(2x + 6)^2 , apply the chain rule to differentiate:
We first use the substitution u=2x+6 u = 2x + 6 , so y=u2 y = -u^2 . The derivative dydu=2u \frac{dy}{du} = -2u .
Since u=2x+6 u = 2x + 6 , the derivative dudx=2 \frac{du}{dx} = 2 . Applying the chain rule, we have:

dydx=dydududx=2u2=4(2x+6)=8x24 \frac{dy}{dx} = \frac{dy}{du} \cdot \frac{du}{dx} = -2u \cdot 2 = -4(2x + 6) = -8x - 24

Step 2: Determine where the derivative is positive
A function is increasing when its derivative is positive, so we set the derivative greater than zero:

8x24>0 -8x - 24 > 0

Solve for x x :

8x>24 -8x > 24

x<3 x < -3

Step 3: Conclusion and multiple-choice validation
The area where the function is increasing corresponds to values of x x less than 3-3. According to the choices provided, the correct answer is:

3>x-3 > x, which corresponds to choice

Therefore, the solution to the problem is 3>x-3 > x.

3

Final Answer

3>x -3 > x

Key Points to Remember

Essential concepts to master this topic
  • Rule: Function increases when derivative is positive
  • Technique: Find f'(x) = -8x - 24, solve -8x - 24 > 0
  • Check: Test x = -4: f'(-4) = 8 > 0, so function increases ✓

Common Mistakes

Avoid these frequent errors
  • Setting derivative equal to zero instead of greater than zero
    Don't solve f'(x) = 0 to find increasing intervals = only gives critical points! This finds where function changes direction, not where it's increasing. Always solve f'(x) > 0 for increasing intervals.

Practice Quiz

Test your knowledge with interactive questions

Find the intersection of the function

\( y=(x+4)^2 \)

With the Y

FAQ

Everything you need to know about this question

Why do we need the derivative to find where a function is increasing?

+

The derivative tells us the slope at every point! When the derivative is positive, the function has a positive slope, meaning it's going upward (increasing).

What does 'ascending area' mean?

+

Ascending area means the same thing as increasing interval - the values of x where the function is rising or going up from left to right.

How do I remember when to use > 0 vs < 0?

+

Think of it this way: positive slope = going up = increasing, so use f'(x) > 0. Negative slope = going down = decreasing, so use f'(x) < 0.

Why is the answer x < -3 instead of x > -3?

+

When we solve 8x24>0 -8x - 24 > 0 , we get 8x>24 -8x > 24 . Dividing by -8 flips the inequality sign, giving us x<3 x < -3 .

Can I check my answer by testing a point?

+

Absolutely! Pick any x-value in your interval (like x = -4) and check if f'(-4) > 0. If yes, your interval is correct!

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Parabola Families questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations