Find the Ascending Region of y=-(x-6)²: Quadratic Function Analysis

Question

Find the ascending area of the function

y=(x6)2 y=-(x-6)^2

Video Solution

Solution Steps

00:00 Find the domain of increase of the function
00:03 Use the shortened multiplication formulas to open the parentheses
00:09 Negative times positive is always negative
00:14 Note the coefficient of X squared, negative - sad function
00:22 Examine the function's coefficients
00:27 Use the formula to find the vertex point
00:32 Substitute appropriate values and solve to find the vertex point
00:46 This is the X value at the vertex point
00:51 In a maximum parabola, the domain of increase is before the vertex point
00:57 And this is the solution to the question

Step-by-Step Solution

To solve this problem, follow these steps:

The function given is y=(x6)2 y = -(x-6)^2 . This indicates that the parabola opens downwards because of the negative sign.

Step 1: Identify the vertex of the parabola:

The vertex form of a parabola is y=a(xh)2+k y = a(x-h)^2 + k . Here, the vertex is at (6,0) (6, 0) .

Step 2: Determine the interval where the function is increasing:

Since the parabola opens downwards, the function is increasing as it approaches the vertex from the left.

Thus, the function is increasing for x<6 x < 6 .

Therefore, the correct answer is x<6 x < 6 .

Answer

x < 6