Find the Descending Area of y=(x+5)²+2x: Quadratic Function Analysis

Find the descending area of the function

y=(x+5)2+2x y=(x+5)^2+2x

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Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:00 Find the domain of decrease of the function
00:03 Use the shortened multiplication formulas to expand the parentheses
00:11 Collect like terms
00:24 Note the coefficient of X squared, positive - smiling function
00:29 Observe the function's coefficients
00:34 Use the formula to find the vertex point
00:44 Substitute appropriate values and solve to find the vertex point
00:51 This is the X value at the vertex point
00:56 In a minimum parabola, the domain of decrease is before the vertex point
01:01 And this is the solution to the question

Step-by-step written solution

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1

Understand the problem

Find the descending area of the function

y=(x+5)2+2x y=(x+5)^2+2x

2

Step-by-step solution

To determine where the function y=(x+5)2+2x y = (x+5)^2 + 2x is decreasing, we need to follow these steps:

  • Step 1: Differentiate the Function
    The function is y=(x+5)2+2x y = (x+5)^2 + 2x . First, we expand and simplify it:
    y=(x+5)2+2x=x2+10x+25+2x=x2+12x+25 y = (x+5)^2 + 2x = x^2 + 10x + 25 + 2x = x^2 + 12x + 25 .
    Now, compute the derivative:
    y=ddx(x2+12x+25)=2x+12 y' = \frac{d}{dx} (x^2 + 12x + 25) = 2x + 12 .
  • Step 2: Identify Intervals of Decrease
    Set the derivative less than zero to find where the function is decreasing:
    2x+12<0 2x + 12 < 0 .
    Solve for x x :
    2x<12 2x < -12
    x<6 x < -6 .

Therefore, the function y=(x+5)2+2x y = (x+5)^2 + 2x is decreasing for x<6 x < -6 .

The correct answer is x<6 x < -6 .

3

Final Answer

x<6 x < -6

Practice Quiz

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Find the intersection of the function

\( y=(x-2)^2 \)

With the X

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