Find the Missing Term in (3x-8)(-4+?) = -3x²-4x+32

Binomial Expansion with Missing Terms

Complete the missing element

(3x8)(4+?)=3x24x+32 (3x-8)(-4+?)=-3x^2-4x+32

❤️ Continue Your Math Journey!

We have hundreds of course questions with personalized recommendations + Account 100% premium

Step-by-step video solution

Watch the teacher solve the problem with clear explanations
00:12 Let's find the missing term.
00:15 Use Y as our unknown. Great job so far!
00:20 Now, open those parentheses. Multiply each number by each other. Take your time!
00:41 Next, calculate the products. You're doing well!
00:56 Now, reduce where you can and gather like terms. Almost there!
01:21 Factor out any common terms on both sides. Keep going!
01:30 Isolate Y, our unknown.
01:36 And that's how we solve the problem! Well done!

Step-by-step written solution

Follow each step carefully to understand the complete solution
1

Understand the problem

Complete the missing element

(3x8)(4+?)=3x24x+32 (3x-8)(-4+?)=-3x^2-4x+32

2

Step-by-step solution

To solve this problem, we'll follow these steps:

  • Step 1: Expand the binomial expression using the distributive property.
  • Step 2: Compare the resulting polynomial's coefficients with the given expression's coefficients.
  • Step 3: Solve for the missing element.

Now, let's work through each step:
Step 1: Express (3x8)(4+?)(3x-8)(-4+?) using the distributive property:
(3x)(4)+(3x)(?)(8)(4)(8)(?)(3x)(-4) + (3x)(?) - (8)(-4) - (8)(?).
This simplifies to: 12x+3x(?)+328(?)-12x + 3x(?) + 32 - 8(?).

Step 2: Compare with 3x24x+32-3x^2 - 4x + 32, equaling terms by degree:
- The constant term (32) already matches.
- The xx term is 12x+3x(?)=4x-12x + 3x(?) = -4x.
- The x2x^2 term arises from 3x(?)3x(?).

Step 3: Solve for the missing element by aligning coefficients:
3x(?)=3x23x(?) = -3x^2, therefore ?=x? = -x.
Thus, the missing element is x-x.

Therefore, the solution to the problem is x-x, which corresponds to choice 2.

3

Final Answer

x -x

Key Points to Remember

Essential concepts to master this topic
  • Distributive Property: Expand (3x-8)(-4+?) by multiplying each term
  • Coefficient Matching: Compare x², x, and constant terms: 3x(?) = -3x²
  • Verification: Substitute ? = -x back into original equation to confirm ✓

Common Mistakes

Avoid these frequent errors
  • Ignoring the x² term when comparing coefficients
    Don't focus only on the x and constant terms = missing the key insight! The x² term comes from multiplying 3x by the missing term, so 3x(?) = -3x² means ? = -x. Always analyze all polynomial terms systematically.

Practice Quiz

Test your knowledge with interactive questions

\( (3+20)\times(12+4)= \)

FAQ

Everything you need to know about this question

Why does the missing term create an x² term?

+

When you multiply 3x 3x by the missing term ? ? , you get 3x? 3x \cdot ? . If ?=x ? = -x , then 3x(x)=3x2 3x \cdot (-x) = -3x^2 , which matches our target expression!

How do I know which terms to compare?

+

After expanding, group terms by their degree: all x2 x^2 terms together, all x x terms together, and all constants together. Then match coefficients with the given polynomial.

What if I get confused during the expansion?

+

Use the FOIL method or distributive property step by step: (3x8)(4+?)=3x(4)+3x(?)+(8)(4)+(8)(?) (3x-8)(-4+?) = 3x(-4) + 3x(?) + (-8)(-4) + (-8)(?) . Take it one multiplication at a time!

Can the missing term be a number instead of a variable?

+

Look at the target expression! Since we need 3x2 -3x^2 , and this comes from 3x? 3x \cdot ? , the missing term must contain x. A plain number couldn't create the x2 x^2 term.

How can I check my answer quickly?

+

Substitute your answer back: (3x8)(4+(x))=(3x8)(4x) (3x-8)(-4+(-x)) = (3x-8)(-4-x) . Expand this and verify it equals 3x24x+32 -3x^2-4x+32 !

🌟 Unlock Your Math Potential

Get unlimited access to all 18 Algebraic Technique questions, detailed video solutions, and personalized progress tracking.

📹

Unlimited Video Solutions

Step-by-step explanations for every problem

📊

Progress Analytics

Track your mastery across all topics

🚫

Ad-Free Learning

Focus on math without distractions

No credit card required • Cancel anytime

More Questions

Click on any question to see the complete solution with step-by-step explanations