Complete the missing element
(a+?)(a+3)=a2+3a+2ab+6b
To solve this problem, we'll approach it by expanding and comparing terms:
- Step 1: Apply the distributive property (FOIL method) to expand (a+?)(a+3).
- Step 2: Compare each term in the expansion with the corresponding term in a2+3a+2ab+6b.
- Step 3: Identify and solve for the missing element.
Let's execute these steps:
Step 1: Consider the expression (a+b)(a+3).
Using distributive property, it expands to:
(a+b)×(a+3)=a×a+a×3+b×a+b×3.
This gives us:
=a2+3a+ab+3b.
Step 2: Now, compare this expansion to the given expression a2+3a+2ab+6b.
Step 3: From the comparison, we have:
- a2 terms match.
- 3a terms match.
- For the ab term, ab should match 2ab, implying b=2b. Therefore, the missing term must contribute an additional b, making it b+ab=2ab. Thus, b=2.
- For the constant term, 3b=6b, leading to the same conclusion.
Therefore, the solution to the problem is 2b.