Find the Missing Term in the Equation: x² + ? + 9 = (x + 3)²

Question

Fill in the blanks:

x2+?+9=(x+3)2 x^2+\text{?}+9=(x+3)^2

Video Solution

Solution Steps

00:00 Complete the missing
00:03 We'll use the shortened multiplication formulas to open the parentheses
00:10 In this case X is the A
00:14 and 3 is the B
00:18 We'll substitute according to the formula
00:37 We'll identify the difference and complete the unknown
00:41 And this is the solution to the question

Step-by-Step Solution

To solve this problem, let's start by expanding the expression on the right side of the equation using the formula for the square of a sum.

Step 1: Expand (x+3)2 (x + 3)^2 :

  • Using the formula (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2, we substitute a=xa = x and b=3b = 3.
  • We have: (x+3)2=x2+2×x×3+32(x + 3)^2 = x^2 + 2 \times x \times 3 + 3^2.
  • Simplifying, we get: x2+6x+9x^2 + 6x + 9.

Step 2: Compare with the given expression:

  • The left side of the equation is x2+?+9x^2 + \text{?} + 9.
  • From our expansion, we see x2+6x+9x^2 + 6x + 9 matches the structure x2+?+9x^2 + \text{?} + 9.
  • This implies the missing term ? \text{?} is 6x6x.

Therefore, the missing term in the expression x2+?+9=(x+3)2 x^2 + \text{?} + 9 = (x + 3)^2 is 6x 6x .

Answer

6x 6x