Complete the Polynomial Equation: Solve for x and y Blanks in (x^2+y)^2+(y^2+x)^2

Question

Fill in the blanks:

(x2+y)2+(y2+x)2=?(x2+1)+2xy[?]+y2[?] (x^2+y)^2+(y^2+x)^2=?(x^2+1)+2xy\lbrack?\rbrack+y^2\lbrack?\rbrack

Video Solution

Solution Steps

00:00 Complete the missing
00:04 We will use the shortened multiplication formulas to open the parentheses
00:19 We will calculate the squares and products
00:37 We will find common factors and factor out of parentheses
01:24 And this is the solution to the question

Step-by-Step Solution

To solve this problem, we'll follow these steps:

  • Step 1: Expand the squares (x2+y)2(x^2+y)^2 and (y2+x)2(y^2+x)^2.
  • Step 2: Combine like terms from the expansions.
  • Step 3: Compare the result to the right-hand side of the equation.

Now, let's work through each step:

Step 1: Expand the expressions:
(x2+y)2=(x2)2+2(x2)(y)+y2=x4+2x2y+y2(x^2 + y)^2 = (x^2)^2 + 2(x^2)(y) + y^2 = x^4 + 2x^2y + y^2
(y2+x)2=(y2)2+2(y2)(x)+x2=y4+2y2x+x2(y^2 + x)^2 = (y^2)^2 + 2(y^2)(x) + x^2 = y^4 + 2y^2x + x^2

Step 2: Combine the expansions:
(x2+y)2+(y2+x)2=x4+2x2y+y2+y4+2y2x+x2(x^2+y)^2 + (y^2+x)^2 = x^4 + 2x^2y + y^2 + y^4 + 2y^2x + x^2
Combine like terms:
=x4+x2+y4+y2+2xy(x+y)= x^4 + x^2 + y^4 + y^2 + 2xy(x+y)

Step 3: Compare with (x2+1)+2xy[?]+y2[?](x^2+1) + 2xy\lbrack?\rbrack + y^2\lbrack?\rbrack:
The complete expression terms include (x2+1)(x^2+1), a term linked to 2xy(x+y)2xy(x+y), and a term in y2y^2 which should account for y4+y2y^4 + y^2 similarity.

Therefore, the solution to the problem is that the blanks should be filled with x2,(x+y),y2+1x^2,(x+y),y^2+1.

Answer

x2,(x+y),y2+1 x^2,(x+y),y^2+1